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zhannawk [14.2K]
3 years ago
6

PLEASE HELP 100 POINTS!!!

Chemistry
2 answers:
babunello [35]3 years ago
5 0

Answer:

1. A double replacement chemical equation is a reaction in which the cations and anions of the compounds that react exchange their positions forming new compounds. Double replacement reaction usually leads to the formation of water, a precipitate or a gas as one of the products.

Example of a double replacement reaction:

CaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->CaSO_{4}(s)+2NaCl(aq)

2. The above equation obeys the Law of conservation of mass as the number of atoms of each element on the reactant side is equal to that of the product side. So the overall mass on reactant side will be equal to that on the product side.

CaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->CaSO_{4}(s)+2NaCl(aq)

Mass of each reactant per mole:

(1 * Ca + 2 * Cl)=(1*40.08g/mol) + (2*35.45g/mol)=110.98g/mol

(2*Na)+(1*S)+(4*O)=(2*22.99g/mol)+(1*32.07g/mol)+(4*16.00g/mol)=142.04g/mol

Total mass on reactant side = (110.98+142.04) g/mol= 253.02g/mol

Mass of each product per mole:

(1*Ca)+(1*S)+(4*O)=(1*40.08g/mol)+(1*32.06g/mol)+(4*16.00g/mol)=136.14g/mol

(2*Na)+(2*Cl)=(2*22.99g/mol)+(2*35.45g/mol)=116.88g/mol

Total mass on product side = (136.14+116.88)g/mol=253.02g/mol

Total mass on reactant side = Total mass on product side =253.02g/mol

So, it obeys the law of conservation of mass as the total mass remains same before and after the reaction.

3. In a chemical reaction, mass is conserved that means the mass of reacting species is equal to the mass of the products formed. Similarly the total number of atoms of each element is also conserved in a chemical reaction.

Read more on Brainly.com - brainly.com/question/11737614#readmore

Explanation: Look it up next time

sergey [27]3 years ago
4 0

1. A double replacement chemical equation is a reaction in which the cations and anions of the compounds that react exchange their positions forming new compounds. Double replacement reaction usually leads to the formation of water, a precipitate or a gas as one of the products.

Example of a double replacement reaction:

CaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->CaSO_{4}(s)+2NaCl(aq)

2. The above equation obeys the Law of conservation of mass as the number of atoms of each element on the reactant side is equal to that of the product side. So the overall mass on reactant side will be equal to that on the product side.

CaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->CaSO_{4}(s)+2NaCl(aq)

Mass of each reactant per mole:

(1 * Ca + 2 * Cl)=(1*40.08g/mol) + (2*35.45g/mol)=110.98g/mol

(2*Na)+(1*S)+(4*O)=(2*22.99g/mol)+(1*32.07g/mol)+(4*16.00g/mol)=142.04g/mol

Total mass on reactant side = (110.98+142.04) g/mol= 253.02g/mol

Mass of each product per mole:

(1*Ca)+(1*S)+(4*O)=(1*40.08g/mol)+(1*32.06g/mol)+(4*16.00g/mol)=136.14g/mol

(2*Na)+(2*Cl)=(2*22.99g/mol)+(2*35.45g/mol)=116.88g/mol

Total mass on product side = (136.14+116.88)g/mol=253.02g/mol

Total mass on reactant side = Total mass on product side =253.02g/mol

So, it obeys the law of conservation of mass as the total mass remains same before and after the reaction.

3. In a chemical reaction, mass is conserved that means the mass of reacting species is equal to the mass of the products formed. Similarly the total number of atoms of each element is also conserved in a chemical reaction.

Read more on Brainly.com - brainly.com/question/14056754#readmore

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Answer : The molality of NaCl is, 1.95 mol/kg

Explanation :

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The dissociation NaCl will be,

NaCl\rightarrow Na^++Cl^{-}

So, Van't Hoff factor = Number of solute particles = Na^++Cl^{-} = 1 + 1 = 2

Now put all the given values in the above formula, we get:

2^oC=2\times (0.512^oC/m)\times m

m=1.95mol/kg

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Answer:

Explanation:

Entropy is the degree of randomness or disorderliness of as system. The more random a system tends, the more positive the entropy. Gases have the highest entropy whereas solids have little to no entropy.

When a reaction goes from one initally with a lower entropy to one with a higher entropy, the change in entropy, ΔS is postive. ΔS is negative when a reaction goes from one with a higher entropy to one with lower entropy.

When there is no entropy change, both the reactants and products are in the same state.

In the first reaction, UF₆ is in a gaseous phase and it was seperated into two gaseous products, 238-UF₆ and 235-UF₆. Therefore, ΔS is zero i.e no change in entropy of the system.

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