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kati45 [8]
3 years ago
12

HELP me, this question not even really hard actually...

Chemistry
1 answer:
zheka24 [161]3 years ago
8 0
This is a hypothesis question. This is an educated guess, basically. In my opinion, I think the tails side would hold more water.
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The theory of continental drift was widely unaccepted until scientists started using ________ the map the ocean floor.
Bumek [7]

Answer:

B. SONAR (Sound Navigation Ranging)

Explanation:

Just took the test

4 0
3 years ago
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Which type of formula represents the simplest whole-number ratio of atoms of the elements in a compound?
sleet_krkn [62]
The empirical formula represents the simplest whole number shows the simplest whole number ratio of atoms in a compound.  An example of this is the empirical formula for glucose (C₆H₁₂O₆) is C₃H₆O₃.  

I hope this helps.  Let me know if anything is unclear.
5 0
3 years ago
Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.
insens350 [35]
Given:
Iron, 125 grams T
1 = 23.5 degrees Celsius, T2 = 78 degrees Celsius.  

Required:
Heat produced in kilojoules  

Solution:
The molar mass of iron is 55.8 grams per mole. SO we need to change the given mass of iron into moles.  
 
Number of moles of iron = 125 g/(55.8 g/mol) = 2.24 moles  
<span>
Q (heat) = nRT = nR(T2 = T1)</span>
Q (heat) = 2.24 moles (8.314 Joules per mol degrees Celsius) (78.0 degrees Celsius – 23.5 degrees Celsius)
<u>Q (heat) = 1014.97 Joules or 1.015 kilojoules</u> <span>This is the amount of heat produced in warming 125 g f iron.</span>
7 0
3 years ago
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
If gas is $4.00/gal, how much does it cost to travel from Portland, Maine, to Orlando, Florida (a distance of 1,500 mi)? Give yo
AlexFokin [52]

it cost $200 , the answer is not $6000

6 0
3 years ago
Read 2 more answers
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