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zhannawk [14.2K]
3 years ago
9

Which proffesion is likely to use a radiation shield?

Chemistry
2 answers:
marusya05 [52]3 years ago
7 0
Probably Geologist, due to the problem of nuclear radiation caused by reactors and bombs
Anni [7]3 years ago
5 0
My answer -

<span> The profession which uses a radiation shield is a geologist. This profession is involved in studying the solid and liquid matter in the Earth along with it are the processes and history that helped shaped it.

P.S

Happy to help you have an AWESOME!!! day ^-^
</span>
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Is water a solution?<br><br> no<br><br> yes
Advocard [28]

Answer:

no, water is a solvent

Explanation:

A solution is a homogeneous mixture of two substances, so water can only be part of a solution when there is something (a solute) mixed with it, like salt, making it salt water.

Hope that helps.

5 0
3 years ago
What is the balanced form of the equation C2H6 + O2→CO2+H2O?
Ede4ka [16]

Answer:

- 2C2H6 + 7O2→4CO2+6H2O

Explanation:

8 0
3 years ago
g In the elimination reaction of t-butanol and t-butyl bromide. A. They have a common intermediate and require a strong base B.
11111nata11111 [884]

Answer:

Both reactions share a common intermediate and differ only in the leaving group

Explanation:

The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.

Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.

In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.

6 0
3 years ago
How do you solve questions 6 and 7
bearhunter [10]

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6 0
3 years ago
A 3.82-g sample of magnesium nitride is reacted with 7.73 g of water. mg3n2 (s) + 3 h2o (â) â 2 nh3 (g) + 3 mgo (s) the yield of
horrorfan [7]
The reaction is properly written as

Mg₃N₂ (s) + 3 H₂O (l) --> 2 NH₃<span> (g) + 3 MgO (s) 

Molar mass of Mg</span>₃N₂ = 100.95 g/mol
Molar mass of H₂O = 18 g/mol
Molar mass of MgO = 40.3 g/mol

Moles Mg₃N₂: 3.82/100.95 = 0.0378
Moles H₂O: 7.73/18 = 0.429 

Theo H₂O required for available Mg₃N₂: 0.0378*3/1 = 0.1134 mol
Hence, the limiting reactant is Mg₃N₂.
Thus,

Theoretical Yield = 0.0378 mol Mg₃N₂ * 3 mol MgO/Mg₃N₂ * 40.3 g/mol
Theo Yield = 4.57 g

Percent Yield = Actual Yield/Theo Yield * 100
Percent Yield = 3.60 g/4.57 g * 100 =<em> 78.77%</em>
5 0
3 years ago
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