Answer:
n = 1.24 moles
Explanation:
Given that,
Mass = 153 grams
Molar mass of KClO₃ = 122.55 g/mol
We need to find the number of moles.
We know that,
No. of moles = given mass/molar mass
So,
![n=\dfrac{153}{122.55 }\\\\n=1.24](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B153%7D%7B122.55%20%7D%5C%5C%5C%5Cn%3D1.24)
So, there are 1.24 moles in 153 g of KClO₃.
Sexual reproduction promotes adaptations, increases genetic diversity, and increases chances of survival.
Answer:
Hypothesis---experiments----results----conclusion.
Explanation:
First we make a hypothesis means a statement about why the tree looks unhealthy. In this segment of scientific method we have to test the hypothesis through experimentation. After that we have to take the readings of various parts of the tree and analyze the data to find out the problem. In the next step, we have to made the results on the basis of the data that is obtained. In the last we have to write the conclusion of the analysis and see the hypothesis.
Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other.
Answer:
5.01%
Explanation:
Density of vinegar = mass/volume
Mass of 10.00 mL = density x volume
= 1.006 x 10 = 10.06 g
From the equation of reaction:
![CH_3COOH(aq)+NaOH(aq)-->CH_3COONa(aq)+H_2O(l)](https://tex.z-dn.net/?f=CH_3COOH%28aq%29%2BNaOH%28aq%29--%3ECH_3COONa%28aq%29%2BH_2O%28l%29)
1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.
mole of NaOH = molarity x volume
= 0.5062 x 0.01658
= 0.008392796 mole
0.008392796 mole of NaOH will therefore require 0.008392796 mole of CH3COOH.
mass of CH3COOH = mole x molar mass
= 0.008392796 x 60.052
= 0.504 g
Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%
= 5.01%
The percent by mass of acetic acid in the vinegar is 5.01%