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4 years ago

What happens to the speed of the

Physics

1 answer:

Andrew [12]4 years ago

8 0

Answer:

The speed stays constant after the force stops pushing.

Explanation:

Speed always stays constant when the force stops pushing it.

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The brakes of a 125 kg sled are applied while it is moving at 8.1 m/s, which exerts a force of 261 N to slow the sled down. How

sammy [17]

Answer:

15.7 m

Explanation:

m = mass of the sled = 125 kg

v₀ = initial speed of the sled = 8.1 m/s

v = final speed of sled = 0 m/s

F = force applied by the brakes in opposite direction of motion = 261

d = stopping distance for the sled

Using work-change in kinetic energy theorem

- F d = (0.5) m (v² - v₀²)

- (261) d = (0.5) (125) (0² - 8.1²)

d = 15.7 m

6 0

3 years ago

Suppose you pour 0.250 kg of 20.0°C water into a 0.600 kg aluminum pan off the stove with a temperature of 173°C. Assume that th

lapo4ka [179]

Answer:

$T_f=5.0116^{\circ}C$

Explanation:

Given:

mass of water, $m_w=0.25\ kg$

initial temperature of water, $T_i_w=20^{\circ}C$

initial temperature of pan, $T_i_p=173^{\circ}C$

mass of pan, $m_p=0.6\ kg$

mass of water evapourated, $m_v=0.03\ kg$

specific heat of water, $c_w=4186\ J.kg^{-1}.K^{-1}$

specific heat of aluminium pan, $c_a=900\ J.kg^{-1}.K^{-1}$

latent heat of vapourization, $L=2256000\ J.kg^{-1}$

<u>Using the equation of heat:</u>

<em>Here, initially certain mass of water is vapourised first and then the remaining mass of water comes in thermal equilibrium with the pan.</em>

$m_p.c_a.(T_{ip}-T_f)=m_v.L+(m_w-m_v).c_w.(T_f-T_{iw})$

$0.6\times 900\times (173-T_f)=0.03\times 2256000+(0.25-0.03)\times 4186\times (T_f-20)$

$T_f=5.0116^{\circ}C$

5 0

3 years ago

When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?

Vinvika [58]

Answer:

Explanation:

V=IR I= curren V=volt R=resistor

8=2.R 8/2=R R=4

5 0

3 years ago

. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. T

Serggg [28]

Answer:

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:

For this exercise let's use the relationship between momentum and momentum.

I = F t = Δp

in this case the final velocity is zero

F t = 0 -m v₀

F = m v₀ / t

in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

F₁ = -p₀ / 0.1

F₁ = - 10 p₀

barrier collapses

F₂ = -p₀ / 1

let's look for the relationship of the forces

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

5 0

3 years ago

An interstellar space probe is launched from Earth. After a brief period of acceleration it moves with a constant velocity, 70.0

sleet_krkn [62]

Answer:

22.26 years

, 15.585 light years , 11.13 light years

Explanation:

$t' = t/(\sqrt{1-(v/(c*v)/c)}$

= $15.9/\sqrt{(1-0.7*0.7)}$

= 22.26 years

0.7*c*22.26 years

=15.585 light years

0.7*c*15.9

=11.13 light years

3 0

3 years ago