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kupik [55]
3 years ago
6

What type of force is needed to accelerate an object? What direction will the object accelerate?

Physics
2 answers:
laila [671]3 years ago
6 0
I think this question is fishing for "NET" force.

That means any force that's not cancelled by another force
on the same object that's equal and opposite (so that the two
of them would add up to zero and have no effect at all).

When there's a 'net' force on the object ... meaning that the whole 
GROUP of ALL forces on the object is not balanced and not zero ...
then the object accelerates in the direction of the net force.
Kay [80]3 years ago
3 0
That just depends on the mass of the object and I think it will accelerate forwards

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A stone is dropped from a height of 49m and simultaneously another ball is thrown upward from the ground with a speed of 40m/s.
Lilit [14]

Answer:

S1 = 1/2 g t^2     distance stone falls in time t

S2 = Vy t - 1/2 g t^2   distance thrown stone rises in time t

H = 49 = S1 + S2 = Vy t

t = 49 / 40 sec   time when stones meet

Check:

Stone 1 falls:      1/2 g t^2 = 1/2 * 9.8 * (49 / 40)^2 = 7.35 m

Stone 2 rises :  40 * (49 / 40) - 1/2 * 9.8 (49 / 40)^2 = 41.65 m

5 0
3 years ago
If a box has a length of 10.0 cm, a width of 20.0 cm, and a height of 5.00 cm, then what is its volume in m^3?
lesya692 [45]

Explanation:

Solution,

Given:-

  • Length=10 cm
  • Width= 20 cm
  • Height= 5 cm
  • Volume =?

Now,

By using the formula of volume of a cuboid, we have

  • volume=length×width×height
  • volume=10 cm×20 cm×5 cm
  • volume=1000 cm³
  • volume= 1×10×10×10×10 cm³
  • volume=(1×10⁴) cm³

Hence, last option is the correct answer.

6 0
3 years ago
To determine the pressure in a fluid at a given depth with the air-filled cartesian diver, we can employ Boyle's law, which stat
aniked [119]

Answer:

The pressure at this depth is 1.235\cdot P_{atm}.

Explanation:

According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:

\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

V_{1}, V_{2} - Initial and final volume.

P_{1}, P_{2} - Initial and final pressure.

If we know that V_{2} = 0.81\cdot V_{1}, then the pressure ratio is:

\frac{P_{2}}{P_{1}} = 1.235

If P_{1} = P_{atm}, then the final pressure of the gas is:

P_{2} = 1.235\cdot P_{atm}

The pressure at this depth is 1.235\cdot P_{atm}.

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Answer: C. 50j

Explanation:

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<h2>Olivia is on a Swing at Playground - Option 2 </h2>

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