What type of force is needed to accelerate an object? What direction will the object accelerate?

2 answers:

6 0

I think this question is fishing for "NET" force.

That means any force that's not cancelled by another force
on the same object that's equal and opposite (so that the two
of them would add up to zero and have no effect at all).

When there's a 'net' force on the object ... meaning that the whole
GROUP of ALL forces on the object is not balanced and not zero ...
then the object accelerates in the direction of the net force.

Kay [80]3 years ago

3 0

That just depends on the mass of the object and I think it will accelerate forwards

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Why are computer simulations useful in studying phenomena in the universe?

kenny6666 [7]

Computer simulation is useful because it helps in the prediction of what will likely happen in the future using data from past events.

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It helps in the prediction of what will likely happen in the future using data from past events.
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5 0

2 years ago

Starting from rest, a 2-m-long pendulum swings from an angleof

Andrews [41]

Answer:

D.) 1m/s

Explanation:

Assume the initial angle of the swing is 12.8 degree with respect to the vertical. We can calculate the vertical distance from this initial point to the lowest point by first calculate the vertical distance from this point the the pivot point:

$L_1 = L*cos(12.8) = 2*0.975 = 1.95 m$

where L is the pendulum length

The vertical distance from the lowest point to the pivot point $L_2$ is the pendulum length 2m

this means the vertical distance from this initial point to the lowest point is simply:

$L_3 = L_2 - L_1 = 2 - 1.95 = 0.05 m$

As the pendulum travel (vertically) from the initial point to the bottom point, its potential energy is converted to kinetic energy:

$E_p = E_k$

$mgh = mv^2/2$

where m is the mass of the pendulum, g = 10 m/s2 is the constant gravitational acceleration, h = 0.05 is the vertical it travels, v is the pendulum velocity at the bottom, which we are trying to solve for.

The m on both sides of the equation cancel out

$v^2 = 2gh = 2*10*0.05 = 1$