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3 years ago

What type of force is needed to accelerate an object? What direction will the object accelerate?

2 answers:

6 0

I think this question is fishing for "NET" force.

That means any force that's not cancelled by another force
on the same object that's equal and opposite (so that the two
of them would add up to zero and have no effect at all).

When there's a 'net' force on the object ... meaning that the whole
GROUP of ALL forces on the object is not balanced and not zero ...
then the object accelerates in the direction of the net force.

Kay [80]3 years ago

3 0

That just depends on the mass of the object and I think it will accelerate forwards

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Why must you balance an equation to describe correctly what happens in a chemical reaction

wariber [46]

Where you get all the steps when you finally get a reaction . Ex, vinegar and baking soda you go step by step.

Hope this helps :)

5 0

3 years ago

A sample of an ideal gas initially occupies a volume of 6 L. The pressure of the sample is then doubled while it is cooled to on

Troyanec [42]

Answer:

V₂= 1 L

Explanation:

Given that

Volume occupies V₁= 6 L

Initial pressure = P₁

Initial temperature = T₁

The final pressure =P₂ = 2 P₁

Final volume =V₂

Final temperature = T₁/3

As we know that equation for ideal gas

P V = m R T

P=pressure, V=volume, T=temperature

m=mass ,R=gas constant

Now from mass conservation

$m=\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}$

$\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}$

$\dfrac{P_1\times 6}{RT_1}=3\times \dfrac{2P_1V_2}{RT_1}$

6 = 3 x 2 V₂

V₂= 1 L

So the final volume will be 1 L

4 0

3 years ago

An archer puts a 0.30 kg arrow to the bowstring. An average force of 201 N is exerted to draw the string back 1.3 m.a. Assuming

Vlad [161]

Answer:

Explanation:

Given

mass of archer $m=0.3\ kg$

Average force $F_{avg}=201\ N$

extension in arrow $x=1.3\ m$

Work done to stretch the bow with arrow

$W=F\cdot x$

$W=201\times 1.3=261.3\ m$

This work done is converted into kinetic Energy of arrow

$W=\frac{1}{2}mv^2$

where v= velocity of arrow

$261.3=\frac{1}{2}\times 0.3\times v^2$

$v=\sqrt{1742}$

$v=41.73\ m/s$

(b)if arrow is thrown vertically upward then this energy is converted to Potential energy

$W=mgh$

$261.3=0.3\times 9.8\times h$

$h=\frac{261.3}{0.3\times 9.8}$

$h=88.87\ m$

4 0

3 years ago

A 0.03 kg baby sea turtle moves across the sand toward the ocean at 0.3 m/s. What is her kinetic energy in Joules?

lina2011 [118]

Answer:

.00135 j

Explanation:

K.E. = 1/2 m v^2

= 1/2 * .03 * .3^2 = .00135 j

4 0

2 years ago

On a dry day, just after washing your hair to remove natural oils and drying it thoroughly, run a plastic comb through it. Small

Hitman42 [59]

When the surface of the comb rubs on your hair, the comb is electrically charged. When the comb comes close to the paper, the charge on the comb causes charge separation on the paper bits. Since paper is neutral, positive and negative charges are equivalent. The charge on the comb charges the area of the bit of paper nearest the comb to the opposite. Thus, the bits of paper become attracted to the comb.

5 0

3 years ago