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k0ka [10]
3 years ago
10

A force of 99 N causes a box to accelerate at a rate of 12 m/s2. What is the mass of the box?

Physics
1 answer:
ira [324]3 years ago
5 0


m = F/a

m = 99/11 = 9

The answer is 9 Kg

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69 MPH

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Two kids are playing tag. The first kid is running at an unknown speed chasing the other. The first kid has a mass of 25 kg and
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3 years ago
The nuclear fuel distribution in a nuclear reactor is chosen so that when in operation the wall temperature of the reactor is a
cestrela7 [59]

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Explanation:

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8 0
3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
givi [52]

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,

f = f_0 (\frac{v_0}{v_0-v})

Here,

f_0 = Frequency of Source

v_s = Speed of sound

f = Frequency heard before slowing down

f' = Frequency heard after slowing down

v  = Speed of the train before slowing down

So if the speed of the train after slowing down will be v/2, we can do a system equation of 2x2 at the two moments, then,

The first equation is,

f = f_0 (\frac{v_0}{v_0-v})

300 = f_0 (\frac{343}{343-v})

(300*343) - 300v = 343f_0

Now the second expression will be,

f' = f_0 (\frac{v_0}{v_0-v/2})

290 = (343)(\frac{v_0}{343-v/2})

290*343-145v = 343f_0

Dividing the two expression we have,

\frac{(300*343) - 300v}{290*343-145v} = 1

Solving for v, we have,

v = 22.12m/s

Therefore the speed of the train before and after slowing down is 22.12m/s

6 0
3 years ago
Can someone help me with this please?​
Nikolay [14]

Answer:

Explanation:

umm... try 30

4 0
3 years ago
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