No, both the cars do not have the same velocity.
Velocity is a vector quantity and it is the rate of change of displacement with time or change in speed with direction.
Velocity has both magnitude and direction. So when you are in a car going 70 km/h and another car goes in the opposite direction at 70 km/h their velocities are different.
How?
Consider your car as moving in the positive direction, so its velocity will be 70 km/h and for the car moving in the opposite direction, since the direction is opposite, the velocity of that car will be -70 km/h. This is because, the velocity is a vector quantity that has both magnitude and direction. For one car, the direction is positive and for the other one the direction is negative.
Plutonium= Pu, 94, 244,94,94
Chromium= Cr, 24,52, 24,24
Neon = Ne, 10,20,10,10
Gold= Au, 79,197,79,79
Radon = Ra ,86,222,86,86
Answer:
D) - 0.72 secs
Explanation:
Parameters given:
Height of bridge = 40ft = 12.19 m
Initial velocity of Bill's stone = 0m/s
Initial velocity of Ted's stone = 10m/s
We find the time it take Bill's stone to bit the river and the time it takes Ted's stone to hit the river. Then we find the time difference.
Using one of the equations of motion:
For Bill:
S = ut + ½gt²
Where g = 9.8 m/s
12.19 = 0 + ½*9.8*t²
t² = 12.19/4.9 = 2.49
t = 1.58 secs
For Ted:
S = uT + ½gT²
12.19 = 10*T + ½*9.8*T²
=> 4.9T² + 10T - 12.19 = 0
Using quadratic formula and retaining only the positive value, we get that:
T = 0.86 secs
Time difference between Bill's throw and Ted's throw is:
0.86 - 1.58 = - 0.72 secs
In reality, this means that Ted must throw his stone 0.72 secs before Bill throws his for both stones to land the same time.
The rocket would have gone 125 m away in deep space.The speed when it has gone 300 m is 76.7 m/s.
Answer:
The distance the rocket traveled is 125 m. The speed when it has gone 300 m is 76.7 m/s.
Explanation:
According to the equations of motion, if an object is moving with constant acceleration, then the distance travelled by the object with that acceleration and within a specific time can be obtained as
Since the initial velocity is given as u = 0 at t = 0. Then at t = 10 s, the acceleration is given by 2.5 m/.
Thus,
s= 0 + (×2.5×)=125 m.
Thus, the rocket would have gone 125 m away in deep space.
Similarly, if it had gone 300 m then its speed can be determined using the third equation of motion.
Since, here v is unknown and u is known as 0 with a = 2.5 m/.
2× 9.8×300=v²
5880=v²
Thus, the speed v =
So, the speed when it has gone 300 m is 76.7 m/s.
Answer:
The normal force is the force that the floor does as a reaction of the gravitational force that an object does against the floor (is the resistance that objects have when other objects want to move trhough them, and the force comes by the 3rd Newton's law, and this is specially used in cases where the first object is fixed, like walls or the floor). With this in mind, the point in where the normal force will be greater is the point that is closer to the center of mass of the object (the point with more mass)
If the wheels are in the extremes of the object, and the center of mass is in the middle of the object, the normal force will be equal. Now if for example, you put a little mass in one end of the object, now the center of weight displaces a little bit and is not centered, and the side is where you put the weight on will receive a bigger normal force from the floor than the other side.