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inna [77]
2 years ago
11

Aude slipped on ice going 7.6 m/s .What was her velocity before she hit the wal?

Physics
1 answer:
Mkey [24]2 years ago
6 0

Answer:

Define universal gravitational constant. Why is newton's law of gravitation called universal law?

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5 0
3 years ago
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How is capacitance related to the distance between the plates of a capacitor?
svetlana [45]

Answer:C

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3 years ago
Weightlessness occurs when an object applies a reaction force to another object. Please select the best answer from the choices
Nina [5.8K]

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3 years ago
The electric field at the center of a ring of charge is zero. At very large distances from the center of the ring along the ring
Daniel [21]

Answer:

z = 1.16m

Explanation:

The electric field in a point of the axis of a charged ring, and perpendicular to the plane of the ring is given by:

E_z=\frac{Qz}{(z^2+r^2)^{\frac{3}{2}}}

z: distance to the plane of the ring

r: radius of the ring

Q: charge of the ring

you have that:

E_{z->0} = 0

E_{z->∞} = 0

To find the value of z that maximizes E you use the derivative respect to z, and equals it to zero:

\frac{dE_z}{dz}=Q[\frac{1}{(z^2+r^2)^{3/2}}+z(-\frac{3}{2})\frac{1}{(z^2+r^2)^{5/2}}(2z)]=0\\\\(z^2+r^2)^{5/2}=3z^2(z^2+r^2)^{3/2}\\\\(z^2+r^2)^2=3z^4\\\\z^4+2z^2r^2+r^4=3z^4\\\\2z^4-2z^2r^2-r^4=0\\\\z^2_{1,2}=\frac{-(-2)+-\sqrt{4-4(2)(-1)}}{2(2)}=\frac{2\pm 3.464}{4}\\\\

you take the positive value:

z^2=\frac{2+3.464}{4}=1.366\\\\z=1.16m

hence, the distance in which the magnitude if the electric field is maximum is 1.16m

7 0
3 years ago
What are two processes that transfer water into the atmosphere
Ira Lisetskai [31]
Water enters the atmosphere through evaporation, transpiration, excretion and sublimation: Transpiration is the loss of water from plant

Hope this helped you! :D
4 0
3 years ago
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