Answer:
32000cm^3
Explanation:
Length L be base length
h be the height
Volume=V
V=L^2h
Surface area if box= L^2+4lh=4800
Solving for h
(4800-l^2/4L)=h
1200L-L^3/4=h
Substitute for h in V =L^2h
v=1200L-L^3/4
Differenting =1200-3*L^2/4=0
L=√(1600)=40
Substitute L=40
In V=1200L-L^3/4
Hence 1200*40-40^4/4=32000cm^3
Answer: 1.04N
Explanation:
Given
q1 = 2*10^-6C
q2 = 3.6*10^-6C
r = 0.25m
k = 9*10^9
Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."
F =(kq1q2) / r²
F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²
F = 0.0648/0.0625
F = 1.04N
The type of electrostatic force between the charges is the repulsive force
The answer is B hope this helps
The answer is c.
hope this helps! :)
