<u>Answer:</u> The amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles
<u>Explanation:</u>
We are given:
Moles of oxygen gas = 9.3 moles
The chemical equation for the reaction of oxygen gas and hydrogen sulfide follows:

<u>For hydrogen sulfide:</u>
By Stoichiometry of the reaction:
3 moles of oxygen gas reacts with 2 moles of hydrogen sulfide
So, 9.3 moles of oxygen gas will react with =
of hydrogen sulfide
<u>For sulfur dioxide:</u>
By Stoichiometry of the reaction:
3 moles of oxygen gas produces 2 moles of sulfur dioxide
So, 9.3 moles of oxygen gas will produce =
of sulfur dioxide
Hence, the amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles
Answer:
c-from last moving to slow-moving particle during particle collision
Explanation:
during conduction, thermal energy is transferred
Answer: 103.8 g of
, 0.65 moles of
Explanation:
To calculate the moles :

Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
According to stoichiometry :
3 moles of
produce = 2 moles of 
Thus 0.975 moles of
will produce=
of 
Mass of 
Thus 103.8 g of
will be produced.
Answer:
17.04%
Explanation:
Actual Value = 173.1
Measured Value = 143.6
Percent error is obtained using the equation;
Percent error = (Measured - Actual) / Actual ]* 100
Percent error = [ (143.6 - 173.1) / 173.1 ] * 100
The absolute value of (Measured - Actual) is taken,
Percent Error = [29.5 / 173.1 ] * 100
Percent Error = 0.1704 * 100 = 17.04%
Hello there!
The correct answer is Ag⁺.
If we look at the solubility rules, it says that most chlorides are soluble, <u>except</u><em> </em>with Ag⁺, and Pb²⁺.
I hope this helps!
Brady<u><em /></u>