Answer:
<em>C</em> H2SO4 = 9.79 M
Explanation:
- molarity (M) ≡ # dissolved species / V sln
- H2SO4 ↔ H3O+ + SO4-
∴ %w/w H2SO4 = 960% = g H2SO4 / g sln * 100
⇒ 9.6 = g H2SO4 / g sln
calculation base: 1000 g sln
⇒ g H2SO4 = 9600g
⇒<em> </em>mol<em> </em>H2SO4 =<em> </em>9600 g H2SO4 * ( mol H2SO4/ 980g H2SO4 ) = 9.796 mol H2SO4
⇒ V sln = 1000g sln / 1000g/L = 1 L sln
∴ ρ H20 ≅ 1000 Kg/m³ = 1000 g/L
⇒ <em>C</em> H2SO4 = 9.796 mol H2SO4 / 1 L sln
⇒ <em>C</em> H2SO4 = 9.796 M
The moon phases maybe? Can I see the passage possibly?
Answer:
H₂ (g) + O₂ (g) ⇒ H₂O (g)
Explanation:
Hydrogen and oxygen gas both exist as diatomic molecules. The water is in gaseous state due to the heat given off by the combustion reaction.
Answer is: 48,25 torr.
Raoult's Law: p = x(solv) · p(solv)
p - <span>vapour pressure of a solution.
</span>x(solv) - <span>mole fraction of the solvent.
</span>p(solv) - <span>vapour pressure of the pure solvent.
</span>n(ethanol) = 950g ÷ 46,07g/mol = 20,62 mol.
x(solv) = moles of solvent ÷ total number of moles
x(solv) = 20,62 ÷ 21,77 = 0,965.
p = 0,965 ·50,0 torr = 48,25 torr.
