Answer:
64640.92 psi
Explanation:
True stress ( psi ) True strain
49300 0.11
61300 0.21
<u>Determine the true stress necessary to produce a true plastic strain of 0.25</u>
бT1 = 49300
бT2 = 61300
бT3 = ?
∈T1 = 0.11
∈T2 = 0.21
∈T3 = 0.25
note : бTi = k ∈Ti^h
∴ 49300 = k ( 0.11 )^h ----- ( 1 )
61300 = k ( 0.21)^h ------ ( 2 )
solving equations 1 and 2 simultaneously
49300/61300 = ( 0.11 / 0.21 )^h
0.804 = (0.52 )^h
next step : apply logarithm
log ( 0.804 ) = log(0.52)^h
h = log 0.804 / log (0.52)
= 0.33
back to equation 1
49300 = k ( 0.11 )^0.33
k = 49300 / (0.11)^0.33
= 102138
therefore бT3 = K (0.25)^h
= 102138 ( 0.25 )^ 0.33
= 64640.92
Answer:
a)0.185g^2
b)4μg^2(
Micrograms)
c)12.167hm^3( cubic hectometer)
Explanation:
To solve this problem, we must first use the calculator to solve each of the points, then knowing the number of zeros on the left or on the right, we choose a unit with which it is better to see the unit
A)
(430 kg)^2=184900kg^2=0.185g^2
B)
(0.002 mg)^2=4x10^-6mg^2=4μg(
Micrograms)
c)
(230 m)^3=12167000m^3=12.167hm^3( hectometer)
Answer:
ser gay
Explanation:
no es malo y se fjfjdj gracias
