Joe's Painting: 20x + 100 = y
Steve's Painting: 15x + 120 = y
x = hours worked
y = total income
We can find when the two equations intersect by making them equal to each other. That means we put an equal sign in the middle. So, it would look something like this:
20x + 100 = 15x + 120
First, we have to move the 100 by subtracting it from both sides.
20x = 15x + 120 - (100)
20x = 15x + 20
Then, we need to move the 15x by subtracting it from both sides.
20 - (15x) = 20
5x = 20
Lastly, we need to divide 5 from both sides.
5x = 20/5
x = 4
Therefore, Joe and Steve would have to work for 4 hours in order for their models to be equal to each other.
Step-by-step explanation:
Remember that in a linear function of the form
,
is the slope and
is the why intercept.
Part A. Since
, its slope is 2 and its y-intercept is 6
Now, to find the slope of
we are using the slope formula:

where
is the slope
are the coordinates of the first point
are the coordinates of the second point
From the table the first point is (-1, -12) and the second point is (0, -6)
Replacing values:




The slope of f(x) is bigger than the slope of g(x), which means the line represented by f(x) is stepper than the line represented by g(x).
Part B. To find the y-intercept of f(x) we are taking advantage of the fact that the y-intercept of a linear function occurs when x = 0, so we just need to look in the table for the value of f(x) when x = 0. From the table
when
; therefore the y-intercept of
is -6.
We already know that the y-intercept of g(x) is 2. Since 2 is bigger than -6, function g(x) has a greater y-intercept.
Y=9.25 (short answer but hope this helped u)
3 * N = 1
The multiplicative inverse is just the reciprocal of the number. The reciprocal is just " flipping " the number. So the reciprocal of 3 (or 3/1) is 1/3. And any time u multiply a number by its multiplicative inverse (reciprocal), the result is 1
3 * 1/3 = 3/3 = 1.....so N is ur multiplicative inverse
<span>sixteen and nine hundred eighty-five hundredths
six-thousandths
two hundred thirty-eight hundredths</span>