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nignag [31]
3 years ago
9

What is the particle that is labeled with a question mark (?) in the diagram?

Chemistry
2 answers:
joja [24]3 years ago
8 0

The answer is (b)= a quark

Nat2105 [25]3 years ago
5 0

Answer is: quark.

Quark is a type of elementary particle and a fundamental constituent of matter.

Quarks form composite hadrons (protons and neutrons). Protons and neutrons are in the nucleus of an atom.

Hadrons include baryons (protons and neutrons) and mesons.

There are six types of quarks: up, down, strange, charm, bottom, and top.

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Sulphuric acid is the on

Explanation:

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How many valence electron does sulfur
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Sulfur has 6 valence electron

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8 0
3 years ago
Determine whether each phrase describes carboxylic acids or esters.
Thepotemich [5.8K]

Answer:

Carboxylic acids produce hydrogen bonds amongst themselves and possess lower vapor pressure. They generally possess a sour odor. When an acid and a base react with each other to produce salt and water and comprises the combination of hydrogen and hydroxide ions, the reaction is termed the neutralization reaction. Thus, when carboxylic acid reacts with base the reaction is termed neutralization.

On the other hand, esters are known for their pleasant fragrances. They do not produce hydrogen bonds amongst themselves and possess higher vapor pressure. A hydration reaction in which free hydroxide dissociates the ester bonds between the glycerol and fatty acids of a triglyceride, leading to the formation of free fatty acids and glycerol is termed saponification.

Thus, the given blanks can be filled with carboxylic acid, carboxylic acid, esters, esters, esters, and carboxylic acid.

8 0
3 years ago
What type of reaction is shown below c10H8+12O2 10co2+4H2O
MakcuM [25]

Answer:

Explanation:

Combustion.  Have fun with that.

7 0
2 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0°c is 4.48. what is the value of ka for hbro?
elena-14-01-66 [18.8K]

The solution would be like this for this specific problem:

Given:

 

pH of a 0.55 M hypobromous acid (HBrO) at 25.0 °C =  4.48

 

[H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-] <span>

Ka = (3.31 x 10^-5)^2 / 0.55 = 2 x 10^-9</span>

 

To add, Hypobromous Acid does not require acid adjustment, which is necessary for chlorine-based product and is stable and effective in pH ranges of 5-9.<span>

</span>Hypobromous Acid combines with organic compounds to form a bromamine. Chlorine also combines with the same organic compounds to form a chloramine. <span>It is also one of the least expensive intervention antimicrobial compounds available.</span>

8 0
3 years ago
Read 2 more answers
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