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nignag [31]
4 years ago
9

What is the particle that is labeled with a question mark (?) in the diagram?

Chemistry
2 answers:
joja [24]4 years ago
8 0

The answer is (b)= a quark

Nat2105 [25]4 years ago
5 0

Answer is: quark.

Quark is a type of elementary particle and a fundamental constituent of matter.

Quarks form composite hadrons (protons and neutrons). Protons and neutrons are in the nucleus of an atom.

Hadrons include baryons (protons and neutrons) and mesons.

There are six types of quarks: up, down, strange, charm, bottom, and top.

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Sydney, Australia, Is in the Southern Hemisphere. Which choice describes the conditions in Sydney on or around December 21
olganol [36]

Answer:warm

Explanation: because it is in the southern hemisphere so in the winter while the northern hemisphere is in a cold winter the southern hemisphere is in a warm winter due to it being in the southern hemisphere where temperatures are really warm in the southern hemisphere.

5 0
3 years ago
Read 2 more answers
In the original mixtures, test tube 1 contained magnesium and a zinc compound, and test tube 2 contained zinc
FromTheMoon [43]

Answer:

Test tube one is a compound because it is 2 elements combine..Test tube to is an element

Explanation:

5 0
3 years ago
Air is compressed from an inlet condition of 100 kPa, 300 K to an exit pressure of 1000 kPa by an internally reversible compress
ElenaW [278]

Answer:

(a) W_{isoentropic}=8.125\frac{kJ}{mol}

(b) W_{polytropic}=7.579\frac{kJ}{mol}

(c) W_{isothermal}=5.743\frac{kJ}{mol}

Explanation:

Hello,

(a) In this case, since entropy remains unchanged, the constant k should be computed for air as an ideal gas by:

\frac{R}{Cp_{air}}=1-\frac{1}{k}  \\\\\frac{8.314}{29.11} =1-\frac{1}{k}\\

0.2856=1-\frac{1}{k}\\\\k=1.4

Next, we compute the final temperature:

T_2=T_1(\frac{p_2}{p_1} )^{1-1/k}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.4}=579.21K

Thus, the work is computed by:

W_{isoentropic}=\frac{kR(T_2-T_1)}{k-1} =\frac{1.4*8.314\frac{J}{mol*K}(579.21K-300K)}{1.4-1}\\\\W_{isoentropic}=8.125\frac{kJ}{mol}

(b) In this case, since n is given, we compute the final temperature as well:

T_2=T_1(\frac{p_2}{p_1} )^{1-1/n}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.3}=510.38K

And the isentropic work:

W_{polytropic}=\frac{nR(T_2-T_1)}{n-1} =\frac{1.3*8.314\frac{J}{mol*K}(510.38-300K)}{1.3-1}\\\\W_{polytropic}=7.579\frac{kJ}{mol}

(c) Finally, for isothermal, final temperature is not required as it could be computed as:

W_{isothermal}=RTln(\frac{p_2}{p_1} )=8.314\frac{J}{mol*K}*300K*ln(\frac{1000kPa}{100kPa} ) \\\\W_{isothermal}=5.743\frac{kJ}{mol}

Regards.

8 0
3 years ago
What happen to water when it boils
tatuchka [14]

When water is boiled, the heat energy is transferred to the molecules of water, which begin to move more quickly. Eventually, the molecules have too much energy to stay connected as a liquid. When this occurs, they form gaseous molecules of water vapor, which float to the surface as bubbles and travel into the air.

8 0
3 years ago
SOMEONE HELP ME PLEASE!!! ILL GIVE BRAINLY
nevsk [136]

Answer:

the answer is c

Explanation:

My reasoning is that its most likely

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