For the answer to the question above, I'll show the solution to my answers
moles C = 82.66 g/ 12.0111 g/mol=6.882
<span>moles H = 17.34 g/ 1.008 g/mol=17.20 </span>
<span>17.20/ 6.882 =2.5 => H </span>
<span>6.882 / 6.882 = 1 => C </span>
<span>to get whole numbers multiply by 2 </span>
<span>C2H5 ( empirical formula Molar mass = 29.062 g/mol) </span>
<span>n = pV/RT = 0.732 x 0.158 L/ 0.08206 x 298 K= 0.00473 </span>
<span>molar mass = 0.275/ 0.00473 =58.1 g/mol </span>
<span>58.1 / 29.062 = 2 </span>
<span>multiply by two the empirical formula </span>
<span>C4H10</span>
Key concepts
Density
Mass
Volume
Concentration
Buoyancy
Water
Answer:
P₂ = 13.79 atm
Explanation:
Given data:
Initial volume = 196.0 L
Initial pressure = 1.83 atm
Final volume = 26.0 L
Final pressure = ?
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.83 atm × 196.0 L = P₂× 26.0 L
P₂ = 358.68 atm. L / 26.0 L
P₂ = 13.79 atm
Answer:
b. ΔH and ΔS are negative at all temperatures .
Explanation:
During the process of condensation ,
The gaseous state convert to liquid state ,
Hence , the entropy of the system reduces , i.e. , the randomness decreases .
And the value for entropy is negative ,
hence ,
Δ S = negative ,
Δ H = negative ,
Since ,
The heat is releasing from system .
hence , the most appropriate option will be ΔH and ΔS are negative at all temperatures .
