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3 years ago

11 Which substance can not be broken down by a chemical change?

1 answer:

4 0

(2) Arsenic. It is an element and elements are chemically the simplest units and cannot be broken down by any chemical change.

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A certain sample of a liquid has a mass of 42 grams and a volume of 35 centimeters3. What is the density of the liquid?

BabaBlast [244]

Answer:

1.2 g.cm⁻³

Solution:

Data Given:

Mass = 42 g

Volume = 35 cm³

Formula Used:

Density = Mass ÷ Volume

Putting values,

Density = 42 g ÷ 35 cm³

Density = 1.2 g.cm⁻³

3 0

3 years ago

Read 2 more answers

49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. w

inna [77]

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The value is $\epsilon = 4118.1 \ M^{-1} cm^{-1}$

Explanation:

From the question we are told that

The volume of the stock solution is $V_1 = 49.9 mL = 0.0499 \ L$

The concentration of the stock solution is $C_1 = 0.00292 \ M$

The volume of the diluted solution is $V_2 = 1.00 \ L$

The absorbance is $A = 0.600$

Generally the from the titration equation we have that

$C_1 * V_1 = C_2 * V_2$

=> $0.00292 * 0.0499 = C_2 * 1$

=> $C_2 = 0.0001457 \ M$

Generally from Beer's law we have that

$A = \epsilon * l * C_2$

=> $\epsilon = \frac{A}{ l * C_2 }$

Here l is the length who value is 1 cm because the unit of molar absorptivity coefficient of the dye is $M^{-1} * cm^{-1}$

$\epsilon = \frac{0.600}{ 1 * 0.0001457 }$

=> $\epsilon = 4118.1 \ M^{-1} cm^{-1}$

4 0

3 years ago

An unknown amount of Al203 decomposed producing 215 g of solid aluminum. 2Al2O3=4Al+3O2 How many grams of oxygen gas should be p

natulia [17]

Answer:

191.11 grams of oxygen gas should be produced.

Explanation:

The balanced reaction is:

2 Al₂O₃ → 4 Al + 3 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al₂O₃: 2 moles
Al: 4 moles
O₂: 3 moles

Being the molar mass of each compound:

Al₂O₃: 102 g/mole
Al: 27 g/mole
O₂: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al₂O₃: 2 moles* 102 g/mole= 204 grams
Al: 4 moles* 27 g/mole= 108 grams
O₂: 3 moles* 32 g/mole= 96 grams

Then you can apply the following rule of three: if by stoichiometry 108 grams of aluminum are produced along with 96 grams of oxygen, 215 grams of aluminum are produced along with how much mass of oxygen?

$mass of oxygen=\frac{215 grams of aluminum*96 grams of oxygen}{108grams of aluminum}$

mass of oxygen= 191.11 grams

191.11 grams of oxygen gas should be produced.

6 0

3 years ago

How to solve determine the final temperature when 450.2 grams of aluminum at 95.2°c is placed in an insulated calorimeter with 6

Pavlova-9 [17]

To solve this, we simply equate the change in enthalpy for the two substances since heat gained by water is equal to heat lost of aluminum. We know that the heat capacity of aluminum is 0.089 J/g°C and that of water is 4.184 J/g°C. Therefore:

450.2 (95.2 - T) (0.089) = 60 (T – 10) (4.184)

3,814.45456 – 40.0678 T = 251.04 T – 2,510.4

291.1078 T = 6,324.85456

T = 21.7°C

8 0

3 years ago

Triangle Q T S is shown. Angle A T S is a right angle. An altitude is drawn from point T to point R on side Q S to form a right

Shtirlitz [24]

Answer:

The answer is 6 root 6

Explanation:

On edge

8 0

3 years ago

Read 2 more answers