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Tcecarenko [31]
2 years ago
7

Fill in the equation of the circle which has a diameter with endpoints (-3,2) and (1,-6).

Mathematics
1 answer:
STatiana [176]2 years ago
6 0

The equation of the circle which has a diameter with endpoints (-3,2) and (1,-6) is x² + y² +6x - 4y -15 = 0.

<h3>What is circle?</h3>

Circle is the 2D geometry which is round in shape with radius R.

The diameter with endpoints (-3,2) and (1,-6). is

D  = √ [(1+3)²+(-6-2)²]

D  = 8.944 units

Radius of circle is R = D/2

R = 8.944 units /2

R =4.4721 units

Given is the general form of the equation of a circle passing through a point and having radius R is

(x -h)² +(y - k)² = R²

Substitute the coordinate (h,k) = (-3,2) and radius R = 4.4721

(x +3)² +(y - 2)² = 4.471²

x² + y² +6x - 4y +5 = 20

x² + y² +6x - 4y -15 = 0

Thus, the equation of the circle which has a diameter with endpoints (-3,2) and (1,-6) is x² + y² +6x - 4y -15 = 0.

Learn more about circle.

brainly.com/question/11833983

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Two kinds of crated cargo, A and B, are to be shipped by truck. Each crate of cargo A is 50 cubic feet in volume and weighs 200
BlackZzzverrR [31]

Answer:

The correct answer is option b)

50a+10b<1000; 200a+360b < 7200; a> 0; b>0

Step-by-step explanation:

We are given that Two kind of crated cargo namely A and B to be shipped by truck.

<u>Cargo A:</u>

Volume of each crate of cargo A = 50 cubic ft

Weight of each crate of cargo A = 200 pounds

Let number of crates of cargo A to be shipped = a

Total volume of 'a' crates of cargo A = 50a cubic ft

Total weight of 'a' crates of cargo A = 200a pounds

<u>Cargo B:</u>

Volume of each crate of cargo B = 10 cubic ft

Weight of each crate of cargo B = 360 pounds

Let number of crates of cargo B to be shipped = b

Total volume of 'b' crates of cargo B = 10b cubic ft

Total weight of 'b' crates of cargo B = 360b

Total volume allowed in the truck is 1000 cubic ft

Total volume of 'a' crates of Cargo A and Total volume of 'b' crates of Cargo B = 50a+10b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

50a+10b ....... (1)

Total weight allowed (load limit) in the truck is 7200 pounds

Total weight of 'a' crates of Cargo A and Total weight of 'b' crates of Cargo B = 200a+360b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

200a+360b ....... (1)

And number of crates of cargo A and B are always a positive number.

So, a > 0 and b > 0.

So, the correct answer is option b.

<em>b. 50a+10b<1000; 200a+360b < 7200; a> 0; b>0</em>

3 0
3 years ago
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