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kupik [55]
3 years ago
13

Select all that are true regarding stereoisomers,constitutional isomers, and conformational isomers

Chemistry
1 answer:
Tamiku [17]3 years ago
8 0

Answer:To convert the model of one constitutional isomer to another constitutional isomer one needs to exchange 2 atoms/groups on different atoms.

To convert the model of one stereoisomer to another stereoisomer one needs to exchange 2 atoms/groups bonded to the same carbon.

To convert the model of one conformational isomer to another conformational isomer one only needs to rotate about single bond(s).

Explanation:

Constitutional isomers differ from each other in position of substituents. Hence if we interchange atoms or groups on two different atoms, we get constitutional isomers.

Stereo isomers posses different orientations in space. If two atoms or groups on the same carbon atoms interchange their spatial orientation, we have a different stereoisomer other than the original structure.

Conformers arise by free rotation across single bonds. Different conformers can be created by rotating single bonds.

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How do the cells in your body get energy?
Anastasy [175]
The cells get into your body by the lungs this answer is correct cause i had the same question and my teacher mark it correct
4 0
3 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
Read 2 more answers
a quantity of gas has a volume of 400.0 mL when confined under a pressure of 600.0mm Hg. what will be the new volume of the gas
Alex787 [66]

Answer:

1200 mL

Explanation:

Given data

  • Initial pressure (P₁): 600.0 mmHg
  • Initial volume (V₁): 400.0 mL
  • Final pressure (P₂): 200.0 mmHg
  • Final volume (V₂): ?

For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{600.0mmHg \times 400.0mL}{200.0mmHg}=1200 mL

3 0
3 years ago
What happens when samples of matter interact?
liberstina [14]

Answer:  matter and its interaction with energy. Matter has mass and occupies space. A Substance is matter that cannot be separated into other kinds of matter by physical means.

Explanation:

7 0
2 years ago
200.0 mL of water is added to 300.0 mL of 3.78 M LiClO3, what is the concentration of the resulting solution?
Kamila [148]
Molarity = number of moles/Volume (L). Solve for the number of moles in the initial solution (3.78M = n/0.3 L) and then use that amount of moles and the new volume (0.5 L) to solve for the new Molarity.
4 0
3 years ago
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