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vlada-n [284]
3 years ago
10

For the following reaction, 142 grams of silver nitrate are allowed to react with 22.3 grams of copper . silver nitrate(aq) copp

er(s) copper(II) nitrate(aq) silver(s) What is the maximum amount of copper(II) nitrate that can be formed
Chemistry
1 answer:
Ivan3 years ago
8 0

Answer:

even I have the same dought

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Let's just say I want to get my mixture to a certain pH but I add too much water to my solution. Can I just add the same volume
Dafna11 [192]

Answer:

You can

Explanation:

The concentration doesn't change when its equals out.

4 0
3 years ago
What is mb for CH3NH2….
drek231 [11]

Answer:

A.) K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}

Explanation:

The general Kb expression is:

K_b = \frac{[HA][OH^-]}{[A^-]}

In this equation

-----> Kb = equilibrium constant

-----> [HA] = acid

-----> [A⁻] = base

Since liquids are not included in equilibrium expressions, H₂O should not be present. The products are in the numerator while the reactant are in the denominator. In this reaction, CH₃NH₂ is acting as a base and CH₃NH₃⁺ is acting as an acid.

As such, the expression is:

K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}

7 0
2 years ago
Which of the following units is used to measure force ?
Sati [7]
C.) Newton. & it's S.I. Unit of Force.

Hope this helps!
3 0
3 years ago
Read 2 more answers
Why is it difficult for hydrogen atoms to stick together
Rasek [7]

Answer:

So, the energy of two hydrogen atoms is lower when the two atoms are together than when the two atoms are apart; that is why they stay together.

Explanation:

6 0
3 years ago
A solution is prepared by dissolving 0.23 mol of benzoic acid and 0.27 mol of sodium benzoate in water sufficient to yield 1.00
Monica [59]

Answer:

The pH does not decrease drastically because the NaOH reacts with the <u>D) Benzoic acid</u> present in the buffer solution.

Explanation:

The hydroxide ions will react with acidic part of the solutions, it means the benzoic acid, so it will form the conjugate base, the benzoate ion.

7 0
3 years ago
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