To determine the number of moles of air present in the tank, we assume that air is an ideal gas in order for us to use the following equation,
n = PV/RT
Substituting the known values,
n = (195 atm)(350 L) / (0.0821 L.atm/mol.K)(10 + 273.15 K)
n = 2935.91 moles
Thus, the number of moles of air is approximately 2935.91 moles.
Answer:
9.96 × 10⁸
Explanation:
Step 1: Calculate the diameter of 1 aluminum atom
The diameter of a sphere is 2 times the radius.
d = 2 × 140 pm = 280 pm
Step 2: Convert "d" to m
We will use the conversion factor 1 m = 10¹² pm.
280 pm × 1 m/10¹² pm = 2.80 × 10⁻¹⁰ m
Step 3: Convert the total length (L) to m
We will use the conversion factor 1 m = 100 cm.
27.9 cm × 1 m/100 cm = 0.279 m
Step 4: Calculate the number of atoms of aluminum required
We will use the following expression.
L/d = 0.279 m/2.80 × 10⁻¹⁰ m = 9.96 × 10⁸
Answer:
he heat of combustion per mole for acetylene, C2H2(g), is -1299.5 kJ/mol.
Explanation:
products are CO2(g) and H2O(l), and given that the enthalpy of formation is -393.5 kJ/mol for CO2(g) and -285.8 kJ/mol for H2O(l), find the enthalpy of formation of C2H2(g).
The heat of combustion per mole for acetylene, C2H2(g), is -1299.5 kJ/mol. Assuming that the combustion products are CO2(g) and H2O(l), and given that the enthalpy of formation is -393.5 kJ/mol for CO2(g) and -285.8 kJ/mol for H2O(l), find the enthalpy of formation of C2H2(g).
