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Nikitich [7]
2 years ago
6

A fixed mass of gass occupies a volume of 200cm at 21°c calculate it's volume at standard temperature

Chemistry
1 answer:
elena55 [62]2 years ago
4 0
The answer is in the attachment below:

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Help please !!!
castortr0y [4]

Answer:

B

pls mark

Explanation:

7 0
3 years ago
Read 2 more answers
A flask contains 6g hydrogen gas and 64 g oxygen at rtp the partial pressure of hydrogen gas in the flask of the total pressure
Alex

Answer:

B.3/5p

Explanation:

For this question, we have to remember <u>"Dalton's Law of Partial Pressures"</u>. This law says that the pressure of the mixture would be equal to the sum of the partial pressure of each gas.

Additionally, we have a <em>proportional relationship between moles and pressure</em>. In other words, more moles indicate more pressure and vice-versa.

P_i=P_t_o_t_a_l*X_i

Where:

P_i=Partial pressure

P_t_o_t_a_l=Total pressure

X_i=mole fraction

With this in mind, we can work with the moles of each compound if we want to analyze the pressure. With the molar mass of each compound we can calculate the moles:

<u>moles of hydrogen gas</u>

The molar mass of hydrogen gas (H_2) is 2 g/mol, so:

6g~H_2\frac{1~mol~H_2}{2~g~H_2}=~3~mol~H_2

<u>moles of oxygen gas</u>

The molar mass of oxygen gas (O_2) is 32 g/mol, so:

64g~H_2\frac{1~mol~H_2}{32~g~H_2}=~2~mol~O_2

Now, total moles are:

Total moles = 2 + 3 = 5

With this value, we can write the partial pressure expression for each gas:

P_H_2=\frac{3}{5}*P_t_o_t_a_l

P_O_2=\frac{2}{5}*P_t_o_t_a_l

So, the answer would be <u>3/5P</u>.

I hope it helps!

5 0
3 years ago
Dna contains the template needed to copy itself, but it has no catalytic activity in cells. what catalyzes the formation of phos
Over [174]
I am sure it is DNA polymerase.
I'm a bio major, hope I helped :)
4 0
3 years ago
A potassium-40 sample starts with 50 atoms, and 1.25 billion years later, there are 25 atoms. What is the half-life of potassium
guapka [62]
D. 1.25 billion years
5 0
3 years ago
A certain first-order reaction (a→products) has a rate constant of 9.60×10−3 s−1 at 45 ∘c. how many minutes does it take for the
Alexxandr [17]

The integrated rate law expression for a first order reaction is

ln\frac{[A_{0}]}{[A_{t}]}=kt

where

[A0]=100

[At]=6.25

[6.25% of 100 = 6.25]

k = 9.60X10⁻³s⁻¹

Putting values

ln\frac{100}{6.25}=9.6X10^{-3}t

taking log of 100/6.25

100/6.25 = 16

ln(16) = 2.7726

Time = 2.7726 / 0.0096 = 288.81  seconds

7 0
2 years ago
Read 2 more answers
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