The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)
Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min
The rocket's velocity is 18 miles per minute at that moment.
Answer:
a=1, b=9 and c= 5
Step-by-step explanation:
9/11 divided by 5/11
= 9/11 * 11/5
11 gets cancelled
=9/5
it can also be written as 1* 9/5
Hence here a=1, b=9 and c= 5
<em>Please mark me as brainliest.</em>
(300 ft/2.92 sec)(1 mi/ 5280 ft)(3600 sec/1 hour) = {3001·3600 miles)/(2.92·5280·1 hour) = 91080000 miles/15417.6 hours = 70.05 mph
Answer:
<em>-120m+60</em>
Step-by-step explanation:
You have to distribute the -15 into the numbers in the 8m-4.
So, <u>-15 times 8m</u> plus <u>-15 times -4</u>
-15 times 8m is <u>-120</u>
-15 times -4 is <u>60</u>
Therefore, the answer is -120m+60
