All categories

1 year ago

The bright-line emission spectrum of an element can best be explained by.

1 answer:

7 0

The light emitted by an element when its electrons return to a lower energy state can be viewed as a bright line emission spectrum.

<h3>What is Emission spectrum ?</h3>

The distribution of electromagnetic radiation released by a substance whose atoms have been excited by heat or radiation.

A spectroscope can be used to determine which frequencies have been emitted by a substance.

An emission line will appear in a spectrum if the source emits specific wavelengths of radiation.

This emission occurs when an atom, element or molecule in an excited state returns to a configuration of lower energy.

Learn more about emission spectrum here ;

https://brainly.in/question/556525

#SPJ1

You might be interested in

A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther

sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

$T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )$

1. Calculate the thermometer readings after 0.5 min and 1 min

(a) After 0.5 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}$

(b) After 1 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}$

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

t = t - 1, because the cooling starts 1 min late

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}$

3. Plot the temperature readings as a function of time.

The graphs are shown below.

6 0

2 years ago

Particles of light are known as

Mashcka [7]

HEY DEAR..

The particles of light known as photon.

HOPE ITS HELPFULL

6 0

2 years ago

Read 2 more answers

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

Julli [10]

Answer:

The number of molecules.

Explanation:

7 0

2 years ago

How many moles are in 1.51 x 10^24 molecules of water?

lyudmila [28]

Answer:One mole of HBr has 6.02 x 1

molecules of HBr.

1 mole of HBr = 6.02 x 1

molecules of HBr.-----(a)

X mole of HBr has 1.21 x

molecules of HBr.

X mole of HBr = 1.21 x

molecules of HBr------(b)

Taking ratio of (a) and (b)

X / 1 = 1.21 x

/ 6.02 x 1

X= 2.009 moles.

Explanation:

3 0

3 years ago

Which of the following is generally true of female bones in relationship to male bones?

gtnhenbr [62]

What are the options

6 0

3 years ago