Consider the equation: 2NO2= N2O4. Using ONLY the information given by the equation which of the following changes would increas
1 answer:
You might be interested in
<u>Answer:</u> The moles of bromine gas at equilibrium is 0.324 moles.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
.......(1)
Calculating the initial moles of hydrogen and bromine gas:
- <u>For hydrogen gas:</u>
Moles of hydrogen gas = 0.682 mol
Volume of solution = 2.00 L
Putting values in equation 1, we get:
- <u>For bromine gas:</u>
Moles of bromine gas = 0.440 mol
Volume of solution = 2.00 L
Putting values in equation 1, we get:
Now, calculating the molarity of hydrogen gas at equilibrium by using equation 1:
Equilibrium moles of hydrogen gas = 0.566 mol
Volume of solution = 2.00 L
Putting values in equation 1, we get:
Change in concentration of hydrogen gas = 0.341 - 0.283 = 0.058 M
This change will be same for bromine gas.
Equilibrium concentration of bromine gas =
Now, calculating the moles of bromine gas at equilibrium by using equation 1:
Molarity of bromine gas = 0.162 M
Volume of solution = 2.00 L
Putting values in equation 1, we get:
Hence, the moles of bromine gas at equilibrium is 0.324 moles.