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Rudik [331]
3 years ago
6

Consider the equation: 2NO2= N2O4. Using ONLY the information given by the equation which of the following changes would increas

e the molar concentration at equilibrium of the product N2O4?
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0
By the way I love science. So there are two moles of NO2(g) with an N204(g). Decreasing most moles. So your answer would be "Pressure Increase" Hope his helps.
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At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide:
gayaneshka [121]

<u>Answer:</u> The moles of bromine gas at equilibrium is 0.324 moles.

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}        .......(1)

Calculating the initial moles of hydrogen and bromine gas:

  • <u>For hydrogen gas:</u>

Moles of hydrogen gas = 0.682 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

\text{Molarity of solution}=\frac{0.682mol}{2.00L}=0.341M

  • <u>For bromine gas:</u>

Moles of bromine gas = 0.440 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

\text{Molarity of solution}=\frac{0.440mol}{2.00L}=0.220M

Now, calculating the molarity of hydrogen gas at equilibrium by using equation 1:

Equilibrium moles of hydrogen gas = 0.566 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

\text{Molarity of solution}=\frac{0.566mol}{2.00L}=0.283M

Change in concentration of hydrogen gas = 0.341 - 0.283 = 0.058 M

This change will be same for bromine gas.

Equilibrium concentration of bromine gas = (\text{Initial concentration}-\text{Change in concentration})=0.220-0.058=0.162M

Now, calculating the moles of bromine gas at equilibrium by using equation 1:

Molarity of bromine gas = 0.162 M

Volume of solution = 2.00 L

Putting values in equation 1, we get:

0.162M=\frac{\text{Moles of bromine gas}}{2.00L}\\\\\text{Moles of bromine gas}=(0.162mol/L\times 2.00L)=0.324mol

Hence, the moles of bromine gas at equilibrium is 0.324 moles.

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