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Dmitry_Shevchenko [17]
2 years ago
5

two ships leave a port sailing 18km/h and 26 km/h. Their angle between their directions of travel from the port is 39 °. How far

part are the skips to the nearest km after 2 hours
Mathematics
2 answers:
Allisa [31]2 years ago
6 0
I got 33.02 ➡️ 33km!!
Leya [2.2K]2 years ago
3 0
33km I got it right
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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

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Solve the problem c=3.14d for d
Maksim231197 [3]

Answer:

c = 3.14d \\ d =  \frac{c}{3.14}

It's change of subject. :)

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Williams is six years younger than three times Alex's age Williams is 33 years old how old is Alex A 9 years old
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W = 3A - 6
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Graph y=3x^2 -5 and it's inverse
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<span>Graph y=3x^2 -5 and it's inverse.</span>

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