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2 years ago

Write the following in scientific Notation

Mathematics

1 answer:

nadya68 [22]2 years ago

6 0

Answer:

1. 5.25 x 10^3

2. 1.23 x 10 ^6

3. 6420000

4 14500

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. Using ratios and the Pythagorean Theorem the approximate width is 23.5 inches and the height is inches.

Sergio039 [100]

Given:

There is a ratio given as 16:9 of width to height and diagonal is 27 iniches

Required:

We need to find the value of height

Explanation:

By ratio

$\begin{gathered} \frac{w}{h}=\frac{16}{9} \\ \\ h=\frac{9}{16}w \end{gathered}$

where w is width and h is height

by using pythagorean theorem

$\begin{gathered} 27^2=h^2+w^2 \\ 729=\frac{81}{256}w^2+w^2 \\ \\ 186624=81w^2+256w^2 \\ w^2=553.78 \\ w=23.5\text{ in} \end{gathered}$

to find h

$h=\frac{9}{16}*23.5=13.24\text{ in}$

Final answer:

height is 13.24 inches

8 0

1 year ago

Calculate the area of the square shown on the xy-plane in the diagram.<br> Your answer

nikdorinn [45]

Answer: 50

Find the area of the triangles then multiply by 2.

1/2 x 5 x 10 = 25

25 x 2 = 50

6 0

3 years ago

Y=6x+4 pleSehhjjjjjhbhbbj

pantera1 [17]

Answer:

6-4 = 2 4-4= 0 and 2/2 = 1

So.. Y=1 !

But if you're looking for the slope, and the Y- intercept, which I think you are, then your slope will be 6, and the y-Intercept would be (0,4).

4 0

3 years ago

You read 9.75 pages in your science book and 24.5 pages of a play for English class. It takes you 1.2 minutes to read each page

Arte-miy333 [17]

It takes you 11.7 minutes to read the science book pages and 19.6 minutes to read the play pages. In total, you spent 31.3 minutes reading.

4 0

4 years ago

) A jar contains 4 white balls and 6 black balls. A ball is chosen at random, and its color noted. The ball is then replaced, al

taurus [48]

Answer:

The answer is " $\bold{\frac{2}{5}\ \ and \ \ \frac{6}{13}}$ ".

Step-by-step explanation:

You have 4/10 opportunities to choose a white ball, and there'll be 7 white balls and 6 black balls out of 13, and so the second time they choose a white one is 7/13, as well as the second time they choose a black, 6/13. people will also have a 4/10 chance.

There are 6/10 chances which users pick its black ball and 4 white balls would still be picked, but 9 black balls and out 13 balls and thus, its second and third time you select the white one is 4/13 but you are likely to pick a black for the second time is 9/13.

Taking the diagram of the next tree. The very first draw is marked with a and the second draw is marked with b.

$\to P(a) = \frac{4}{10}\ \ \ \ \ \ \ \ \ P(b) = \frac{6}{10}\\\\\to P(\frac{a2}{a1}) = \frac{7}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{a}{b}) = \frac{4}{13}\\\\\to P(\frac{b2}{a1}) = \frac{6}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{b2}{b1}) = \frac{9}{13}$

Calculating the second drawn ball is white:

$\to P(b2)=P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\$

$=\frac{4}{10}\frac{7}{13}+\frac{6}{10}\frac{4}{13}\\\\=\frac{28}{130}+\frac{24}{130}\\\\=\frac{28+24}{130}\\\\=\frac{52}{130}\\\\=\frac{2}{5}\\\\$

In point b:

$\to P(\frac{b}{a1})= \frac{P(B)P(\frac{a}{b})}{P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\}$

$=\frac{\frac{6}{10} \frac{4}{13}}{\frac{52}{130}}\\\\=\frac{\frac{24}{130}}{\frac{52}{130}}\\\\=\frac{24}{130} \times \frac{130}{52}\\\\=\frac{24}{52}\\\\=\frac{6}{13}\\$

5 0

4 years ago