Ooo im taking chem this semester and just around this subject,
water is neutral and <span>H2CO3cant act as b-l base soo </span>the answer is HCIO4(aq)
Answer:
55.18 L
Explanation:
First we convert 113.4 g of NO₂ into moles, using its molar mass:
- 113.4 g ÷ 46 g/mol = 2.465 mol
Then we<u> use the PV=nRT formula</u>, where:
- P = 1atm & T = 273K (This means STP)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
Input the data:
- 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K
And <u>solve for V</u>:
Number 18 is correct, number 19 is the particles speed up and the substance expands, and number 20 is decrease in volume
Answer:
Nitrogen is the limiting reactant, and
3.74
grams of ammonia is formed.
Explanation:
We have the familiar Haber process equation...
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
Since the mole ratio of
N
2
to
H
2
is
1
:
3
, then for every mole of nitrogen, we would need three moles of hydrogen.
Explanation:
