3 years ago

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Chemistry

1 answer:

earnstyle [38]3 years ago

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Answer:....................................................................

Explanation:.............................................................................

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What is the molecular formula of a compound containing 89% cesium (Cs) and 11% oxygen (O) with a molar mass = 298 g/mol?

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M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11

CsxOy

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x=298*0.89/133=2

y=M(CsxOy)w(O)/M(O)
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Answer: One formula unit of NaCl consists of one cation, whose chemical symbol is $Na^+$ and one anion whose chemical symbol is $Cl^-$

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For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cation is formed by the metal sodium which forms $Na^+$ and the anion is formed by non metal chlorine which forms $Cl^-$ .

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