Answer: 317 joules
Explanation:
The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
In this case,
Q = ?
Mass of aluminium = 50.32g
C = 0.90J/g°C
Φ = (Final temperature - Initial temperature)
= 16°C - 9°C = 7°C
Then, Q = MCΦ
Q = 50.32g x 0.90J/g°C x 7°C
Q = 317 joules
Thus, 317 joules of heat is gained.
The average atomic mass of her sample is 114.54 amu
Let the 1st isotope be A
Let the 2nd isotope be B
From the question given above, the following data were obtained:
- Abundance of isotope A (A%) = 59.34%
- Mass of isotope A = 113.6459 amu
- Mass of isotope B = 115.8488 amu
- Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
- Average atomic mass =?
The average atomic mass of the sample can be obtained as follow:
Thus, the average atomic mass of the sample is 114.54 amu
Learn more about isotope: brainly.com/question/25868336
Answer:
Option C. 13.5 atm
Explanation:
From the question given above, the following data were obtained:
Pressure of Neon (Pₙₑ) = 4.1 atm
Pressure of Argon (Pₐᵣ) = 3.2 atm
Pressure of nitrogen (Pₙ₂) = 6.2 atm
Total pressure (Pₜ) =?
The total pressure in the container can be obtained by adding the pressure of the individual gases. This is illustrated below:
Pₜ = Pₙₑ + Pₐᵣ + Pₙ₂
Pₜ = 4.1 + 3.2 + 6.2
Pₜ = 13.5 atm
Therefore, the total pressure in the container is 13.5 atm
Answer:
covalent bonding becaus of there both non metals
