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PIT_PIT [208]
3 years ago
14

Which element does not combine with sulfur? A.F B. G C. H D.K E. All can combine?

Chemistry
1 answer:
maw [93]3 years ago
8 0
Answer is either B or all of the above. “G” is not an element on the periodic table. If it’s not a typo, then the answer is B.
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Quis critérios foram usadps por dobereiner em sua tentava de organiza os elementos químicos?
anyanavicka [17]

Döbereiner grouped the known elements into <em>triads</em> (sets of three) so that

• The <em>atomic mass of the middle element</em> was approximately the average    of the other two

• The <em>chemical properties of the middle element</em> were between those of the other two

• The <em>physical properties of the middle element</em> were between those of the other two

One example of a triad is Li – Na – K.

(a) Atomic mass of Na = 23.0 u

       Average atomic mass of Li and K = (6.9 u + 39.1 u)/2 = 46.0 u/2 = 23.0 u

(b) Li reacts slowly with water. Na reacts rapidly. Potassium reacts violently.

(c) Melting point of Na = 371 °C.

       Average melting point of Li and K = (454 °C + 330 °C)/2 = 784 °C/2

       = 392 °C

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2 years ago
Wich are the disadvantages of skimming oil spills?
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Diamond has a density of 3.513 g/cm³. The mass of diamonds is often measured in "carats," where 1 carat equals 0.200
Gennadij [26K]

The volume of a 1.86-carat diamond in cubic centimeters is 0.106 cm³

Given,

The density of a diamond is  3.513 g/cm³.

We have to find out the volume of a 1.86-carat diamond in cubic centimeters.

Convert the units of the diamond from carat to grams, we have:

(1.86 carats) x (0.200 g / 1 carat) = 0.372 g

The volume of the diamond is obtained by dividing the mass by the density, therefore using the formula, we get

                            v = m / d

                            v = 0.372 g / (3.51 g/cm³) = 0.1059 cm³

                       or, v = 0.106 cm³ (approx)

Therefore, the volume of a 1.86-carat diamond is approximately 0.106 cm³.

To learn more about the volume, visit: brainly.com/question/1578538

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If 3.06 grams of ammonia (NH₃) react with 0.0350 moles of chromium (III) nitrate as noted by the following equation, what is the
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