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Semmy [17]
3 years ago
9

An alcohol is 58.80 % C and 9.889 % H by mass. The rest is oxygen. What is the empirical formula of the alcohol? Enter the eleme

nts in the order C, H, and then O.
Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

hco I believe

Explanation:

Pretty sure about this, when do you need to put it in?

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A sample of krypton gas with a volume of 10.00 L has a temp of 303 K and exerts
marshall27 [118]

<u>Answer:</u> The final volume will be 14.85 L.

<u>Explanation:</u>

To calculate the final volume when temperature increases, we use Charles' Law.

This law states that volume is directly proportional to the temperature of the gas if number of moles and pressure remains constant.

V\propto T\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 = Initial volume and temperature

V_2\text{ and }T_2 = Final volume and temperature

We are given:

V_1=10L\\&#10;T_1=303K\\&#10;V_2=?L\\&#10;T_2=450K

Putting values in above equation, we get:

\frac{10L}{303K}=\frac{V_2}{450K}

V_2=14.85L

Hence, the final volume of the gas is 14.85L

7 0
3 years ago
Anyone else ever done this? Please help !!
Oksanka [162]

Answers for criss-cross (except Q3) is in the above picture.

5 0
3 years ago
which of the following energy transformation occurs when a skier glides down a hill. A. potential energy is transformed into kin
GarryVolchara [31]
The answer is C. hope this helps ;)
4 0
3 years ago
Convert the following temperatures to Kelvin:
maxonik [38]

Explanation:

A. 100°C to Kelvins

T(K)=T(^oC)+273.15

T(K)=100(^oC)+273.15=373.15 K

B 600°R to Kelvins

(T)^oK=((T)^oR)\times 1.8

(T)^oK=600\times 1.8 K = 1080 K

C. 98°F to Kelvins

(T(K)-273.15)=(T(^oF)-32)\times \frac{5}{9}

(T(K))=(98(^oF)-32)\times \frac{5}{9}+273.15=309.81K

D. 77.4°F to degree Celsius

((T)^oC)=((T)^oF-32)\times \frac{5}{9}

(T)^oC =(77.4^oF-32)\times \frac{5}{9}=25.22^oC

E. 77.4 K to degree Celsius

T(^oC)=T(^K)-273.15

T(^oC)=77.4(K)-273.15=-195.75^oC

F. 77.4°R to degree Celsius

(T)^oC=((T)^oR-491.67)\times \frac{5}{9}

(T)^oC=((77.4)^oR-491.67)\times \frac{5}{9}=-230.15 ^oC

7 0
3 years ago
Draw the two chair conformations of cis 1 chloro 2 methylcyclohexane
Mrrafil [7]
In chair conformations of cyclohexane, Cl group is on the first C and methyl group is on the second C. In the cis conformation both groups should be in the same orientation, either both side chains should be up and up or down and down. In this figure its up and up. 
2 figures are drawn as when the chair conformation flips, the axial groups become equatorial and equatorial groups become axial. But they remain as up or down .
When A flips to B, Cl goes from axial to equatorial and CH3 goes from equatorial to axial but both remain up.

6 0
3 years ago
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