P=w/t
w=15
t=3
therefore, 5 watts (b)
Answer:
Rutherford described the atom as consisting of a tiny positive mass surrounded by a cloud of negative electrons. Bohr thought that electrons orbited the nucleus in quantised orbits. Bohr built upon Rutherford's model of the atom. ... So it was not possible for electrons to occupy just any energy level.
Explanation:
Answer:
The new radius of the trajectory of the particle is four times the previous radius
Explanation:
In order to know what is the radius of the trajectory of the charged particle, if its speed is four times as fast, you take into account the following formula, which describes the radius of a charged particle in a magnetic field:
(1)
If the speed of the particle is for time as fast, that is, v' = 4v, you obtain, in the equation (1):
The new radius of the trajectory of the particle is four times the previous radius
Answer:
P = 6*5 = 30 [kg*m/s]
Explanation:
in order to solve this problem, we must remember that linear momentum is defined as the product of mass by Velocity. This way you can calculate the momentum using the following equation.
P = m*v
where:
P = lineal momentum [kg*m/s]
m = mass = 6 [kg]
v = velocity = 5 [m/s]
P = m*v
P = 6*5 = 30 [kg*m/s]
