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andrew11 [14]
2 years ago
10

If wavelength and speed of a wave are 4 m and 332 m/s respectively, calculate its frequency​

Physics
1 answer:
Furkat [3]2 years ago
4 0

Explanation:

<em>Given </em>

<em>wavelength </em><em>=</em><em> </em><em>4</em><em> </em><em>m</em>

<em>speed </em><em> </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em> </em><em>m/</em><em>s</em>

<em>frequency </em><em>=</em><em> </em><em>?</em>

<em>We </em><em>know </em><em>we </em><em>have </em><em>the </em><em>formula </em>

<em>wavelength</em><em> </em><em>=</em><em> </em><em>speed </em><em>/</em><em> </em><em>frequency </em>

<em>4</em><em> </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em> </em><em>/</em><em> </em><em>frequency </em>

<em>frequency </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em>/</em><em>4</em>

<em>Therefore </em><em> </em><em>frequency </em><em>is </em><em>8</em><em>3</em><em> </em><em>Hertz </em><em>.</em>

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(a) 3.5 Hz

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\omega=\sqrt{\frac{k}{m}}

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k is the spring constant

m is the mass

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k = 160 N/m

m = 0.340 kg

So the angular frequency is

\omega=\sqrt{\frac{160 N/m}{0.340 kg}}=21.7 rad/s

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f=\frac{\omega}{2\pi}=\frac{21.7 rad/s}{2\pi}=3.5 Hz

(b) 0.021 m

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x = A

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The maximum displacement is given by Hook's law:

F=kA

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F is the force applied initially to the spring, so it is equal to the weight of the block:

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Solving for A, we find

A=\frac{F}{k}=\frac{3.34 N}{160 N/m}=0.021 m

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2 years ago
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