How many significant digits should the answer to the following problem have? (2.49303 g) * (2.59 g) / (7.492 g) =
1 answer:
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The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.
<h3>What is Columb's law?</h3>The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.
They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.
The given data in the problem is;
q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C
F is the repulsive force = 36 mN =36 ×10⁶ N
d is the distance = 0.70 m
The Coulomb force is found as;
Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.
To learn more about Coulomb's law, refer to the link;
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Answer:
Explanation:
let this sign be ∅ (titha in degrees)
let coefficient of friction of 0.200 be u
and i be current i= 1.41A
mass m=1.14g/cm m=0.0114g/m
To find the magnetic field from the north will be:
tan ∅= u
∅=
∅=11.3°
The direction:
i L*B cos(∅)= umg
divide both by iLcos(∅) to find B
B= where m=
B=
B=
Answer:
x=1.25m
Explanation:
The <em>Center of mass </em>of the system is defined as the point where whole mass of the body is appeared to be concentrated.
The center of mass of the system is given by
x=
where m1 is mass of man =60 kg
m2 mass of board =20 kg
let the man be at the origin x1 =0 , x2 =5m
by substituting in above formula
x = =
=1.25 m
x=1.25m
So the center of mass of the system is at 1.25 m from man.
