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Vikki [24]
4 years ago
10

A car has a mass of 8000 kg and a kinetic energy of 24,000 J. What is its

Physics
2 answers:
o-na [289]4 years ago
8 0

AnswerB.2.4m/s

Explanations;

24000=1/2×8000×v^2

24000/4000=v^2

√ 6.=v

v=2.4

Aneli [31]4 years ago
4 0

Answer:

2.4

Explanation:

48,000/8000=6

square root of 6 = 2.44948974278

so 2.4

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Divers in Acapulco dive from a cliff that is 65 m high. If the rocks
Alex777 [14]

Answer:

Cool question! First step is to find the time taken to fall

57

m

, then to find the horizontal velocity needed to cover

24

m

in that time. In this case the answer is

7.0

m

s

−

1

.

Explanation:

This is a less typical projectile motion question, but it's still projectile motion. This means the horizontal and vertical directions can be considered separately. We assume that the initial vertical velocity,

u

y

=

0

m

s

−

1

, and we are trying to find the required initial horizontal velocity,

u

x

.

To find the time taken to fall

57

m

:

s

=

u

t

+

1

2

a

t

2

Since

u

=

0

, we can rearrange this to:

t

=

√

2

s

a

=

√

2

⋅

57

9.8

=

3.41

s

The horizontal velocity will be constant (ignoring air resistance), so to cover

24

m

in

3.41

s

will be given by:

v

=

s

t

→

u

x

=

24

3.41

=

7.0

m

s

−

1

Answer link

5 0
2 years ago
In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin
alexandr402 [8]

Answer:

a) v=0.999124c

b) E=7.566*10^{22}

c) E_a=760 times\ larger

Explanation:

From the question we are told that

Distance to Betelgeuse d_b=430ly

Mass of Rocket M_r=20000

Total Time in years traveled T_d=36years

Total energy used by the United States in the year 2000 E_{2000}=1.0*10^20

Generally the equation of speed of rocket v mathematically given by

v=\frac{2d}{\triangle t}

v=860ly/ \triangle t

where

\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\sqrt{(860)^2+(36)^2}

\triangle t=860.7532

Therefore

v=\frac{860ly}{ 860.7532}

v=0.999124c

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2

E=7.566*10^{22}

c)Generally the equation of the energy E_a required to accelerate the rocket mathematically given by

E_a=\frac{E}{E_{2000}}

E_a=\frac{7.566*10^{22}}{1.0*10^{20}}

E_a=760 times\ larger

8 0
3 years ago
How do you explain the differences in the work along the plane and the work through the vertical height?
Elan Coil [88]
There’s no work along the plane, while work increases as the height increases

Another example,
When you’re picking up a box... that’s work
When you are walking WITH the box, no work
8 0
4 years ago
Free body diagram is this correct?
lesya692 [45]

Answer:Yes that is correct

Explanation:

7 0
3 years ago
Read 2 more answers
Plzzz helpp mee guysss!!! plzzzz
kramer
123465798012345678901243567980
3 0
3 years ago
Read 2 more answers
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