vector b is the answer...............
Answer:
Shear resistance of a inclined stirrup is given by
Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)
Explanation:
The shear resistance is checked in accordance with BS8110: Part 1, section 3.5.5. Shear resistance of a inclined stirrup is given by
Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)
where,
Vᵇ=design shear resistance of inclined bars
Asb=cros-sectional area of the inclined bars
Fy=characteristics strength of the stirrups
α=angle between the inclined bars and the axis of the beam
β=angle between the compression strut of inclined bars and the axis of the beam
sᵇ=spacing of the inclined bars
d= effective depth and d'=effective depth minus cover to reinforcement
The shear stress is given by
v=V/bd
where V is the shear force due to ultimate loads. If v is shear stress
Answer:
Pressure = force/area
= 650N/0.12m^2
= 5416.7 to 1 d.p
I got 650N by taking the gravitational field on earth to be 10N/kg.
Weight = mass x gravitational field
= 65 x 10N/kg
= 650
Answer is 5416.7 pascals (Pa)
Or
5308.3 Pa
if gravitational field was taken to be 9.8N/kg
Hope this helps!
It’d be B: severe depressive symptoms
Answer:
the extension would be less the new extension might be 3 cm
Explanation:
