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3 years ago

7

Which is the largest gas giant?

1 answer:

NNADVOKAT [17]3 years ago

4 0

In our solar system......jupiter

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Light rays from an object after passing through a convex lens form an image at the focal point behind the lens (opposite side of

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3 years ago

Identify some common fuels

kozerog [31]

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3 years ago

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Draw in force and velocity vectors at the four marked positions the object below is moving counterclockwise in uniform circular

Ilia_Sergeevich [38]

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3 years ago

Calculate the speed of body moving a distance of 320km in 4h

ololo11 [35]

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Convert hours to seconds -> 4 hrs=14400 s
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6 0

2 years ago

Suppose that a solid ball, a solid disk, and a hoop all have the same mass and the same radius. Each object is set rolling witho

8090 [49]

Answer:

Hoop will reach the maximum height

Explanation:

let the mass and radius of solid ball, solid disk and hoop be m and r (all have same radius and mass)

They all are rolled with similar initial speed v

by the law of conservation of energy we can write

$K_{trans}+K_{rot}= P$

for solid ball

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{ball}\omega^2= mgh_{ball}$

putting $I_{ball}=\frac{2}{5}mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{ball}= 0.071v^2$

now for solid disk

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{disk}\omega^2= mgh_{disk}$

putting $I_{ball}=\frac{1}{2}mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{disk}= 0.076v^2$

for hoop

$[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{hoop}\omega^2= mgh_{hoop}$

putting $I_{hoop}=mr^2 and \omega=\frac{v}{r}$ in the above equation and solving we get

$h_{hook}= 0.10v^2$

clearly from the above calculation we can say that the Hoop will reach the maximum height

5 0

3 years ago