The pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution.
<h3>What is the pH?</h3>
What we call the pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution. We are aware that we can use the relation [H+] [OH-] = 1 * 10^-14 to handle the enormity of this problem.
Now, let us go about solving the problems;
1. pH = -log(1 x 10-7) = 7
2. [H+]= 1 * 10^-14/ 1 x 10^-3
pH = -log( 1 * 10^-11)
pH = 11
3. pH = -log( 1 x 10^-2)
pH = 2
4. pH = -log( 1 x 10^-10)
pH = 10
5. [H+]= 1 * 10^-14/ 1 x 10^-8
[H+]= 1 * 10^-6
pH = 6
Learn more about pH:brainly.com/question/1528974
#SPJ1
Hello,
The correct answer would be:
True.
Inorganic compounds contain: carbon monoxide<span>, </span>carbon dioxide, carbonates,cyanides<span>, </span>cyanates<span>, carbides, and </span><span>thiocyanates
Mark brainliest if helped!</span>
If it’s a negative number and a positive it might be 1.4
Answer:
90.3 kJ/mol
Explanation:
Let's consider the following thermochemical equation.
2 NO(g) + O₂(g) → 2 NO₂(g) ∆H°rxn = –114.2 kJ
We can find the standard enthalpy of formation for NO using the following expression.
∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))
∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol
∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))
ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol
ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol
ΔH°f(NO(g)) = 90.3 kJ/mol
Answer:
Option A. 9.4 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 8 L
Initial temperature (T₁) = 293 K
Final temperature (T₂) = 343 K
Final volume (V₂) =?
V₁ / T₁ = V₂ / T₂
8 / 293 = V₂ / 343
Cross multiply
293 × V₂ = 8 × 343
293 × V₂ = 2744
Divide both side by 293
V₂ = 2744 / 293
V₂ = 9.4 L
Therefore, the final volume of the gas is 9.4 L