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adelina 88 [10]
4 years ago
9

The initial pressure and volume of a gas are 55.16 kilopascals and 0.500 liter. According to Boyle’s law, if the volume of the g

as changes to 0.800 liter, the pressure of the gas will be ____ kilopascals.
Chemistry
1 answer:
Gnesinka [82]4 years ago
7 0

Answer: The final pressure is 34.48kPa

Initial Pressure P1 = 55.16kPa

Initial Volume V1 = 0.500L

Final Pressure P2 = ?

Final Volume V2 = 0.800L

Boyle's law P1V1 = P2 V2

P2 = P1V1/V2

P2 = 55.16*0.5/0.8

P2 = 34.48kPa

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7 0
4 years ago
16) How many photons are contained in a burst of yellow light (589 nm) from a sodium lamp that contains 609 kJ of energy?
Len [333]
The correct answer to this question is this one:

find the energy of one photon:

<span>E=h*<span>c/λ
</span></span>
divide the energy given by the energy of one photon of that wavelength

What I've done so far is convert wave length to m and energy to j. 

E photon = h * x / wave length
E = (6.626 x 10^-43)(3.00 x 10^8) / 587 ^ -9  = 3.38 x 10 ^18 J
3.38 x 10 ^18 J x 1000 kj / 1 j = 3.37 x 10 ^ 16 Kj
609 kJ/  3.37 x 10 ^ 16 Kj =  1.81 x 10 ^ 16

E = (6.626 x 10^-34)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^19 J
3.38 x 10 ^19 J x 1000 kj / 1 j = 3.37 x 10 ^ -16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 18 but the answer is  1.81 × 10^24 photons

3.38 x 10 ^-19 J
should be negative

then 3.38 x 10 ^18 J x 1kJ/1000 J

you're converting from J to kJ.. just like meters to kilometres, you wouldn't multiply you would divide
4 0
3 years ago
Read 2 more answers
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