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2 years ago

6

Carson went shopping for a new video game because of a sale. The price on the tag was $40, but Carson paid $28 before tax. Find

the percent discount.

1 answer:

MatroZZZ [7]2 years ago

7 0

Answer:

Step-by-step explanation:

28/40 ×100 =70 PERCENT

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ALGEBRA 1 HELP URGENT!!

Lelechka [254]

I would tell you but the answer wont show sorry. :)

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3 years ago

WILL GIVE BRAINLIEST!!! The two larger segments below are perpendicular. Find the area of the shaded region to the nearest integ

snow_lady [41]

Answer:

I wont be able to help much and get you till all the way to the end but here is what i know:

Step-by-step explanation:

The radius of the smaller circle is 6, and the longer segment adds up to 12 since 6 + 6 = 12. the area of the whole bigger circle would be 452.389, by using the formula of the area of a circle "πr²". This is what i can tell and the only part I'm confused in how to find the area of JUST the shaded part. I hope this helped a bit!

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2 years ago

Simplify each expression. Assume that all variables are positive.

kozerog [31]

Q1. The answer is $\frac{8x^{3}y^{6} }{27}$

$( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} } \\ \\ 
 \frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\ \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=$
$\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\ \\ 
 (x^{a} )^{b} = x^{a*b} \\ \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } = \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} =$
$= \frac{8x^{3}y^{6} }{27}$

Q2. The answer is 1/16

$(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ 
$
$\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}$

Q3. The answer is $a^{ \frac{7}{6} }$

$a^{ \frac{2}{3} } * a^{ \frac{1}{2} } \\ \\ 
 x^{a}* x^{b} =x^{a+b} \\ \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }$

7 0

3 years ago

Help me please for this question im heavily confused.

Ulleksa [173]

Answer:

a)

Let x = number of candy bars sold

Let y = amount of money earned

b)

y = 0.75x

c)

He should work at the car wash.

Step-by-step explanation:

a)

Let x = number of candy bars sold

Let y = amount of money earned

b)

$42.75/57 = $0.75

Each candy bar costs $0.75

We can confirm that by dividing $38.25/51 = $0.75

1 candy bar sells for $0.75

2 candy bars sell for $0.75 * 2

x candy bars sell for 0.75 * x, or simply 0.75x

The equation is y = 0.75x

c)

y = 0.75x

y = 0.75 * 36

y = 27

Larry raised $27 by selling candy bars last year. This year, he can earn more than that by working at the car wash.

He should work at the car wash.

8 0

3 years ago

Pls solve I will give the barinliest answer plssss

ra1l [238]

Answer:

20 or 3

Step-by-step explanation:

good luck

hope it helps u

need more answers?

just follow me

8 0

2 years ago

Read 2 more answers