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Reptile [31]
3 years ago
9

Prepare 500mL of dextrose 10% using dextrose 2.5% and dextrose 30%. How many milliliters of each are needed?

Chemistry
1 answer:
astraxan [27]3 years ago
5 0

We will call D1 and D2 the volume of dextrose at 2.5% and 30% respectively​

D1 + D2 = 500 (1)​

D1*2,5/100 + D2*30/100 = 500*10/100 (2)​

(2,5D1+30D2)/100 = 50​

2,5D1 +30D2 = 50*100​ = 5.000 (2)

D1 = 500 - D2 Now we clear D1 in (1)

2,5(500-D2) + 30D2 = 5.000 and we substitute in (2)

1.250 - 2,5D2 + 30D2 = 5.000​

27,5D2 = 5.000 - 1.250 = 3.750​

D2 = 3.750/27,5 = 136ml +4/11ml​

D1 = 500ml - 136ml +4/11ml​

D1 = 363ml +7/11ml​

ANSWER 363ml+7/11 ml of dextrose 2,5% and 136ml+4/11 ml dextrose 30%​

\textbf{Spymore}​

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