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svet-max [94.6K]
2 years ago
13

g) If two cars A and B are moving with velocity 60 km/hr and 80 km/hr respectively in the same direction. What will be the relat

ive velocity of B with respect to A? (20 kmhr)​
Physics
1 answer:
tester [92]2 years ago
4 0

Explanation:

Here,

Velocity of A=60km/hr

Velocity of B=80km/hr

Now,

Relative velocity of B with respect to A in the same direction=Velocity of B - Velocity of A

=80km/hr-60km/hr

=20km/hr

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What force is required to push a block (mass m) up an inclined plane that makes an angle of θ with the horizon at a constant vel
Verizon [17]

Answer:

b. mg ( μ · cos θ + sin θ)

Explanation:

Hi there!

Please, see the attached figure for a graphical description of the problem.

We have the following parallel forces acting on the block (in parallel direction to the direction of movement):

F = applied force.

Fr = friction force.

wx = parallel component of the weight.

According to Newton´s second law:

∑F = m · a

Where "m" is the mass of the block and "a" its acceleration.

Then:

F - Fr - wx = m · a

Since the block is to be pushed at a constant velocity, the acceleration is zero. Then:

F - Fr - wx = 0

F = Fr + wx

The applied force has to be equal to the friction force plus the parallel component of the weight to push the block at constant velocity.

The friction force is calculated as follows:

Fr = μ · N

Where N is the normal force and μ is the coefficient of friction.

Notice that the normal force is of the same magnitude as the perpendicular component of the weight, wy.

Let´s apply Newton´s second law in the perpendicular direction to show this:

∑F = m · a

N - wy = m · a

The acceleration of the block in the perpendicular direction is zero. Then:

N - wy = 0

N = wy

And wy can be obtained by trigonometry (see figure):

wy = W · cos θ

N = wy = mg ·  cos θ

The parallel component of the weight is calculated using trigonometry (see figure):

wx = W · sin θ

wx = mg · sin θ

Then the applied force will be:

F = Fr + wx

F = μ · N + mg · sin θ      (N = wy = mg ·  cos θ)

F = μ · mg ·  cos θ  + mg · sin θ

F = mg ( μ · cos θ + sin θ)

The correct answer is the b.

8 0
3 years ago
Which of the following processes forms clouds A. Boiling B.Condensation C.Freezing D.Precipitation
love history [14]

Answer:

B

Explanation:

6 0
3 years ago
Read 2 more answers
How long will your trip take if you travel 4000 m at an average speed of 8m/s
SpyIntel [72]
  • Answer:

<em>500 sec</em>

<em>8 min 20 sec</em>

  • Explanation:

<em>Hi there !</em>

<em />

<em>8 m ................ 1 s </em>

<em>4000 m ........ x s</em>

<em>x = 4000m×1s/8m = 500 sec = 8 min 20 sec</em>

<em />

<em>Good luck ! </em>

8 0
3 years ago
Read 2 more answers
While visiting the beach, you enjoy the warm ocean water, but the sand burns your feet. That night you walk along the beach and
garik1379 [7]

The answer would be B..

Since sand can heat up quickly, it will also cool off quickly. But water takes a long time to heat up and cool down.

8 0
3 years ago
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g
Strike441 [17]

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

3 0
3 years ago
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