These are called neap tides!
Hope this helps :)
Answer:
it will move in the opposite direction because of Newton's 3rd law
Answer:
<em>n =1.33 revolutions</em>
Explanation:
<u>Uniform Circular Motion</u>
The angular speed can be calculated in two different ways:
Where:
v = tangential speed
r = radius of the circle described by the rotating object
Also:
Where:
f = frequency
Solving for f:
Since the frequency is calculated when the number of revolutions n and the time t are known:
We can solve for n:
n=f.t
The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:
Now we calculate f:
Calculating the number of revolutions:
n = 0.04421*30
n =1.33 revolutions
Answer:(a) With our choice for the zero level for potential energy of the car-Earth system when the car is at point B ,
U
B
=0
When the car is at point A, the potential energy of the car-Earth system is given by
U
A
=mgy
where y is the vertical height above zero level. With 135ft=41.1m, this height is found as:
y=(41.1m)sin40.0
0
=26.4m
Thus,
U
A
=(1000kg)(9.80m/s
2
)(26.4m)=2.59∗10
5
J
The change in potential energy of the car-Earth system as the car moves from A to B is
U
B
−U
A
=0−2.59∗10
5
J=−2.59∗10
5
J
(b) With our choice of the zero configuration for the potential energy of the car-Earth system when the car is at point A, we have U
A
=0. The potential energy of the system when the car is at point B is given by U
B
=mgy, where y is the vertical distance of point B below point A. In part (a), we found the magnitude of this distance to be 26.5m. Because this distance is now below the zero reference level, it is a negative number.
Thus,
