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Kruka [31]
3 years ago
13

Water flows through a pipe at an average temperature of T[infinity] = 70°C. The inner and outer radii of the pipe are r1 = 6 cm

and r2 = 6.5 cm, respectively. The outer surface of the pipe is wrapped with a thin electric heater that consumes 300 W per m length of the pipe. The exposed surface of the heater is heavily insulated so that all heat generated in the heater is transferred to the pipe. Heat is transferred from the inner surface of the pipe to the water by convection with a heat transfer coefficient of h = 85 W/m2⋅K. Assume that the thermal conductivity is constant and the heat transfer is one-dimensional. Express the mathematical formulation (the differential equation and the boundary conditions) of the heat conduction in the pipe during steady operation.
Engineering
1 answer:
Paul [167]3 years ago
6 0

Answer:

The differential equation and the boundary conditions are;

A) -kdT(r1)/dr = h[T∞ - T(r1)]

B) -kdT(r2)/dr = q'_s = 734.56 W/m²

Explanation:

We are given;

T∞ = 70°C.

Inner radii pipe; r1 = 6cm = 0.06 m

Outer radii of pipe;r2 = 6.5cm=0.065 m

Electrical heat power; Q'_s = 300 W

Since power is 300 W per metre length, then; L = 1 m

Now, to the heat flux at the surface of the wire is given by the formula;

q'_s = Q'_s/A

Where A is area = 2πrL

We'll use r2 = 0.065 m

A = 2π(0.065) × 1 = 0.13π

Thus;

q'_s = 300/0.13π

q'_s = 734.56 W/m²

The differential equation and the boundary conditions are;

A) -kdT(r1)/dr = h[T∞ - T(r1)]

B) -kdT(r2)/dr = q'_s = 734.56 W/m²

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Semmy [17]

Answer:

There is conversion of energy from one form to another and this justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.

Explanation:

The fuel added to automobile is a chemical energy, which provides thermal energy of the combustion engine of the automobile, which is then converted to mechanical energy of the moving parts of the automobile. Thus, there is conversion of energy from one form to another. This justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.

3 0
3 years ago
Convert 850 nm wavelength into frequency, eV, wavenumber, joules and ergs.
BabaBlast [244]

Answer:

Frequency = 3.5294×10¹⁴ s⁻¹

Wavenumber = 1.1765×10⁶ m⁻¹

Energy = 2.3365x 10⁻¹⁹ J , 1.4579 eV , 2.3365x 10⁻¹² erg

Explanation:

Given the wavelength = 850 nm

1 nm = 10⁻⁹ m

So, wavelength is  850×10⁻⁹ m

The relation between frequency and wavelength is shown below as:

c = frequency × Wavelength

Where, c is the speed of light having value = 3×10⁸ m/s

So, Frequency is:

Frequency = c / Wavelength

Frequency=\frac {3\times 10^8\ m/s}{850\times 10^{-9}\ m}

Frequency = 3.5294×10¹⁴ s⁻¹

Wavenumber is the reciprocal of wavelength.

So,

Wavenumber = 1 / Wavelength  = 1 / 850×10⁻⁹ m

Wavenumber = 1.1765×10⁶ m⁻¹

Also,

Energy=h\times frequency

where, h is Plank's constant having value as 6.62x 10⁻³⁴ J.s

So,

Energy = 6.62x 10⁻³⁴ J.s × 3.5294×10¹⁴ s⁻¹

Energy = 2.3365x 10⁻¹⁹ J

Also,

1 J = 6.24×10¹⁸ eV

So,

Energy = 2.3365x 10⁻¹⁹ × 6.24×10¹⁸ eV

Energy = 1.4579 eV

Also,

1 J = 10⁷ erg

So,

Energy = 2.3365x 10⁻¹⁹ × 10⁷ erg

Energy = 2.3365x 10⁻¹² erg

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3 years ago
What were some challenges engineers faced in designing aqueducts.
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Answer:

Valleys and low-lying areas, hills and mountains, were some of the challenges faced by Roman engineers who built Aqueducts. The first aqueduct was built in Rome around 312 BC. By the 3rd century AD, it became common.

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Answer:

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Explanation:

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A 2-kg plastic tank that has a volume of 0.2m^3 is filled with water. Assuming the density of water is 999 kg/m 3 ; determine th
siniylev [52]

Answer:

Mass of the combined system = 201.8 Kg

Weight of the combined system = 1977.64 N

Explanation:

Given:

Mass of the plastic tank = 2 kg

Volume of the plastic tank = 0.2 m³

Density of water = 999 Kg/m³

Now, the volume of water in the tank =  volume of tank = 0.2 m³

Also,

Mass = Density × Volume

therefore,

Mass of water = 999 × 0.2 = 199.8 Kg

Thus, the combined mass = Mass of tank + Mass of water in the tank

or

the combined mass = 2 + 199.8 = 201.8 Kg

Also,

Weight = Mass × Acceleration due to gravity

or

Weight = 201.8 × 9.8 = 1977.64 N

7 0
3 years ago
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