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Mrrafil [7]
2 years ago
15

A. A crane at a construction site lifts a concrete block with a mass of m = 277 kg from the ground to the top of a building with

a height of h = 22.3 m. How much work did the motor of the crane do? (Assume zero energy loss in the lifting mechanism due to friction.)
b. If the duration of the lift was 2.85 minutes, then what was the average power performed by the crane?
Physics
1 answer:
marysya [2.9K]2 years ago
5 0

a. The work motor of the crane did is 60.6 kJ.

b. The average power performed by the crane is 21.263kW.

<h3>What is work done?</h3>

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is  a crane at a construction site lifts a concrete block with a mass of m = 277 kg from the ground to the top of a building with a height of h = 22.3 m.

a. Work done by motor is  W= F x d

The force is equal to the weight F = mg

So, W = 277 x 9.81 x 22.3

W = 60.6 kJ

Thus, the work done by the motor is  60.6 kJ.

b. The duration of the lift was 2.85 minutes

Power = Work done/ time

Plug the values, we ghave

P = 60.6 x1000 /2.85

P =21.263kW

Thus, the  average power performed by the crane is 21.263kW

Learn more about Work done

brainly.com/question/13662169

#SPJ1

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an electron and a 0.0320-kg bullet each have a velocity of magnitude 510 m/s, accurate to within 0.0100%. within what lower limi
MArishka [77]

for this we apply, Heisenberg's uncertainty principle.

it states that physical variables like position and momentum, can never simultaneously know both variables at the same moment.

the formula is,

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

by rearranging,

Δx = h / 4π * m(e).Δv

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 / 583.9 X 10 ⁻³¹

Δx = 0.011 X 10⁻³

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.032*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 /2.05

Δx =3.23 X 10⁻³² m

therefore, we can say that the lower limits are   0.011 X 10⁻³  m for the electron and  3.23 X 10⁻³² m   for the bullet

To know more about bullet problem,

brainly.com/question/21150302

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6 0
1 year ago
The body went 450 meters within 30 seconds of starting the movement. In what time did the first 50 meters go?
Andrew [12]

3.33 seconds.

<u>Explanation:</u>

We can find the speed of the body using the formula,

Speed = Distance traveled in meters /  time taken in seconds

= 450 m / 30 seconds

= 15 m/s

So per second the distance traveled by the body is 15 m.

So time needed to travel 50 m can be found as,

time = distance/speed

= 50 m / 15 m /s

= 3.33 s

8 0
3 years ago
What causes the sound to have a lower volume when used in a carpeted room​
Viefleur [7K]

Answer:

Correct answer: The carpet material is soft, non-stick and diffuse and therefore absorbs waves.

Explanation:

The room is more acoustic if the walls and ceiling and floor are made of hard and polished material that reflects sound waves well while the carpeted room absorbs sound waves so it is less acoustic. The carpet material is soft, non-stick and diffuse and therefore absorbs waves.

God is with you!!!

4 0
3 years ago
[10 POINTS ❗️❗️ and brainlist :)]
ludmilkaskok [199]
The answer to this is D
6 0
3 years ago
Read 2 more answers
Help!!! I need it today <br> Thank you in advance
svlad2 [7]

Answer:

 F = - k (x-xo) a graph of the weight or applied force against the elongation obtaining a line already proves Hooke's law.

Explanation:

The student wants to prove hooke's law which has the form

          F = - k (x-xo)

To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.

Now for a series of known masses let's get them one by one and measure the spring elongation, building a table of weight vs elongation,

we must be careful when hanging the weights so as not to create oscillations in the spring

we look for the mass of each weight

         W = mg

          m = W / g

and we write them in a new column, we make a graph of the weight or applied force against the elongation and it should give a straight line; the slope of this line is sought, which is the spring constant.

The fact of obtaining a line already proves Hooke's law.

5 0
2 years ago
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