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nirvana33 [79]
3 years ago
13

Friction depends on the types of surfaces involved and how hard the surfaces push together. Please select the best answer from t

he choices provided T F
Physics
1 answer:
LenKa [72]3 years ago
5 0

True: Friction depends on the types of surfaces involved and how hard the surfaces push together.

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5. A backpack weighs 9.2 newtons and has a mass of 5 kg on the moon. What is the
Varvara68 [4.7K]

Answer:

The strength of gravity on the moon is 1.84\ m/s^2.

Explanation:

We have,

Weight of the backpack, W = 9.2 N

Mass, m = 5 kg

It is required to find the strength of gravity on the moon. Weight of an object is given by :

W = mg

g is strength of gravity on the Moon

g=\dfrac{W}{m}\\\\g=\dfrac{9.2\ N}{5\ kg}\\\\g=1.84\ m/s^2

So, the strength of gravity on the moon is 1.84\ m/s^2.

3 0
3 years ago
One speed skater starts across a frozen lake at an average speed of 8 m/s. Ten seconds later, a second speed skater starts from
Luba_88 [7]

Answer:

40 s

Explanation:

After 10 seconds, the first skater would have a 8m/s * 10s = 80 m head start

Let t be the number of seconds after the second skater starts will the second skater overtake the first skater

The distance traveled by the first skater after t seconds is

s_1 = v_1t = 8t

Similarly the distance traveled by the 2nd skater after t seconds is

s_2 = v_2t = 10t

Since the 2nd skater catches up to the 1st one after 80 m behind, the distance traveled by the 2nd one must be 80m greater than the distance of the 1st skater

s_2 = s_1 + 80

We can substitute s_1 = 8t, s_2 = 10t

10t = 8t + 80

2t = 80

t = 80 / 2 = 40 s

7 0
3 years ago
Anything that has mass and occupies space is defined as.
forsale [732]

Answer:

matter is the correct answer.

8 0
2 years ago
Volume of an block is 5 cm3. If the density of the block is 250 g/cm3, what is the mass of the block ?​
wlad13 [49]

Answer:

The mass of the block is 1250g.

Explanation:

Given that the formula for density is ρ = mass/volume. Then you have to substitute the values into the formula :

ρ =  \frac{mass}{volume}

Let density = 250,

Let volume = 5,

250 =  \frac{m}{5}

m = 250 \times 5

m = 1250g

7 0
3 years ago
The engine of a locomotive exerts a constant force of 8.1*10^5 N to accelerate a train to 68 km/h. Determine the time (in min) t
Bumek [7]

Answer:443.1 s

Explanation:

Given

Engine of a locomotive exerts a force of 8.1\times 10^5 N

Mass of train=1.9\times 10^7

Final speed (v)=68 km/h \approx 18.88 m/s

F=ma

so acceleration(a) =\frac{F}{m}=\frac{8.1\times 10^5}{1.9\times 10^7}

a=0.042631 m/s^2

and acceleration is

a=\frac{v-u}{t}

0.042631=\frac{18.88-0}{t}

t=443.089 \approx 443.1 s

8 0
3 years ago
Read 2 more answers
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