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2 years ago

What is the mass of 9.45 mol of aluminum oxide (Al2O3)?

Chemistry

2 answers:

DochEvi [55]2 years ago

6 0

Answer:

964g Al2O3

Explanation:

given: 9.45 mol Al2O3
Find: mass in grams Al2O3

solve:

We know the molar mass of Al2O3 is 101.96 g/mol by looking at the periodic table and adding up the mass.

the set up:

9.45 mol Al2O3 x 101.96g Al2O3/mol Al2O3

the moles cross out and you're left with g as the unit.

so solving

9.45 x 101.96 = 963.52 g = 964 g Al2O3

Wittaler [7]2 years ago

3 0

Answer:

mass = 963.53 grams

Explanation:

mass = moles x molar mass

m = 9.45 x 101.96 (molar mass of Al2O3)

m = 963.53g

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$\bold{\huge{\orange{\underline{ Solution}}}}$

$\bold{\underline{ Given :- }}$

We have 250g of liquid water and it needs to be cool at temperature from 100° C to 0° C
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$\bold{\underline{ To \: Find :- }}$

We have to find the total number of joules released.

$\bold{\underline{ Let's \:Begin:- }}$

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That is, 

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$\sf{ Q = 250 × 4.180 × - 100 }$

$\sf{ Q = 250 × - 418}$

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$\bold{\underline{ Now :- }}$

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