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2 years ago

Select all the equations where x = 3 x=3x, equals, 3 is a solution.

Mathematics

1 answer:

Aneli [31]2 years ago

8 0

H%%786 explanation you have to use inverse operating

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Find the value of k and x2<br> x^2+ 13x + k = 0, x1=-9

Anarel [89]

Given:

The quadratic equation is:

$x^2+13x+k=0$

$x_1=-9$

To find:

The value of k and $x_1$ .

Solution:

We have,

$x^2+13x+k=0$ ...(i)

Putting $x=-9$ , we get

$(-9)^2+13(-9)+k=0$

$81-117+k=0$

$-36+k=0$

$k=36$

Putting $k=36$ in (i), we get

$x^2+13x+36=0$

Splitting the middle term, we get

$x^2+9x+4x+36=0$

$x(x+9)+4(x+9)=0$

$(x+9)(x+4)=0$

$x=-9,-4$

Here, $x_1=-9$ and $x_2=-4$ .

Therefore, the required values are $k=36$ and $x_2=-4$ .

3 0

3 years ago

1 and 2 are complementary angles. 1 and 3 are vertical angles. If

Marizza181 [45]

If angle 1 and angle 2 are <u>complementary, </u>then they add up to 90 degrees. We are given that angle 2 equals 52 degrees.

So we subtract and get our answer:

That's NOT the final answer.

The next step is:

Angle 1 and angle 3 are vertical angles.

Vertical angles are congruent.

So if angle 1 is 38, then angle 3 is also 38.

Now, supplementary angles add up to 180 degrees.

So that's the answer:

180-38=142

142 is the supplement of angle 3.

Hope it helps! :)

Answered by

$***ROSALIND***$

8 0

2 years ago

Ye has his own business. He checks his sales receipts three times a day, his afternoon sales were 50$ more than his mourning sal

IRINA_888 [86]

Answer:

The answer is 150

Step-by-step explanation:

It's 150 because ye evening sales are three times of his afternoon sales.

SO that means you have to times 50x3=150 or you can add 50+50+50=150. there is your answer.

3 0

3 years ago

Read 2 more answers

Change 95.61 to degrees, minutes, and seconds.

12345 [234]

The answers are 95 36 36

6 0

3 years ago

Read 2 more answers

You invest $300 at 4% interest, compounded every year. What will your balance be after 5 years? (Remember, the formula is A = P(

Stells [14]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill\\ P=\textit{original amount deposited}\to &\$300\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5\implies A\approx 364.996$

3 0

3 years ago