In the given situation, the gas is heated under constant volume. As energy is supplied to the system in the form of heat, the frequency of collision between the gas particles increases. This increases the temperature of the gas consequently bringing about a decrease in pressure.
Based on the ideal gas law:
PV = nRT
Here, P/T = nR/V
If P1, T1 and P2, T2 are the pressure and temperature values before and after heating respectively, then since nR/V is a constant in this case, we have
P1/T1 = P2/T2 which is the Gay-Lussac's law.
Answer:
0.50 g Caffeine
Explanation:
Step 1: Given data
Concentration of caffeine by weight in tea leaves: 5.0%
Mass of tea leaves: 10. g
Step 2: Calculate the maximum weight of caffeine that can be isolated
The concentration of caffeine by weight in tea leaves is 5.0%, that is, there are 5.0 g of caffeine per 100 g of tea leaves. The maximum weight of caffeine in 10. g of tea leaves is:
10. g Tea leaves × 5.0 g Caffeine/100 g Tea leaves = 0.50 g Caffeine
Answer:
To obtain a more accurate read on temperature, the researcher should make sure to measure temperature by Celsius degrees rather than Fahrenheit.
Explanation:
Temperature is a measure of heat intensity. In food science experiments, you should always require an exact description of heat intensity. The most commonly used unit of temperature in the laboratory is the Celsius degree because the Celsius temperature scale is based on the boiling and freezing points of pure water. The difference between the points of boiling and freezing temperatures (at 1 atmosphere of air pressure) is divided into 100 equal units, making a Celsius degree 0.01 of the difference between the boiling and freezing points of water, making it the most accurate method of exact temperature reading. It is important to use the Celsius scale if you have a thermometer that reads Celsius and Fahrenheit.
Answer : 70.906 grams of chlorine reacted with hydrogen
Explanation :
Step 1 : Write balanced chemical equation.
The balanced chemical equation for the reaction between hydrogen and chlorine gas is given below.
Step 2 : Find moles of H₂ gas.
The moles of H₂ can be found as
We have 2.0200 g of H₂ and molar mass of H₂ is 2.02 g/mol.
Let us plug in these values to find moles of H₂.
We have 1 mol of H₂.
Step 3 : Find moles of Cl₂ using mole ratio.
The mole ratio of H₂ and Cl₂ is 1 : 1.
The moles of Cl₂ can be calculated as
Step 4 : Find grams of Cl₂.
Molar mass of Cl₂ gas is 70.096 g/mol
Mass of Cl₂ =
We have 70.906 grams of Cl₂