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Dovator [93]
2 years ago
9

Hydrogen bonding is present in all of the following molecular solids EXCEPT ____.a) H2O2 b) PH3 c) H2SO4 d) NH3

Chemistry
2 answers:
In-s [12.5K]2 years ago
7 0

Answer:

b) PH3

Explanation:

NISA [10]2 years ago
4 0

Answer:

answer is Option A

H202.

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The mixing of which pair of reactants will result in a precipitation reaction?
Maru [420]

Answer:

K2SO4(aq) + Ba(NO3)2(aq)

Explanation:

K2SO4(aq) + Ba(NO3)2(aq)= 2KNO3(aq) + BaSO4(s)

The reaction produces BaSO4

Which precipitates as the insoluble product and Soluble KNO3 solution

8 0
3 years ago
. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are
olga nikolaevna [1]

<u>Answer:</u> The standard free energy change of formation of S^{2-}(aq.) is 92.094 kJ/mol

<u>Explanation:</u>

We are given:

K_{sp}\text{ of }Ag_2S=8\times 10^{-51}

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314J/K mol

T = temperature = 25^oC=[273+25]K=298K

K = equilibrium constant or solubility product = 8\times 10^{-51}

Putting values in above equation, we get:

\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ

For the given chemical equation:

Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)

The equation used to calculate Gibbs free change is of a reaction is:  

\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]

The equation for the Gibbs free energy change of the above reaction is:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]

We are given:

\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ

Putting values in above equation, we get:

285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol

Hence, the standard free energy change of formation of S^{2-}(aq.) is 92.094 kJ/mol

8 0
3 years ago
What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter
Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, 31.0^oC

Explanation :

First we have to calculate the heat produced.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of NaOH = 1.52 g

Molar mass of NaOH = 40 g/mol

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole

Now put all the given values in the above formula, we get:

44.5kJ/mol=\frac{q}{0.038mol}

q=1.691kJ

Now we have to calculate the final temperature of solution in the calorimeter.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 20.1^oC

T_2 = final temperature = ?

Now put all the given values in the above formula, we get:

1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)

T_2=31.0^oC

Thus, the final temperature of the solution in the calorimeter is, 31.0^oC

4 0
3 years ago
The isotopes of an element all have the same __(atomic, mass) __number, but they have different __(atomic,mass)__numbers.
Vlad1618 [11]
<h2>The isotopes of an element all have the same __(atomic, mass) __number, but they have different __(atomic,mass)__numbers.</h2>

Explanation:

The isotopes of an element all have the same __atomic  number  __, but they have different __mass __numbers.

The isotopes have same atomic number that is :

  • Same number of electrons
  • Same number of protons
  • same electronic configuration
  • same valence electrons
  • same valency
  • same symbol

The isotopes have different mass number that is :

They differ in number of neutrons .

For example : Isotopes of hydrogen are : H₁¹ , H₁² , H₁³

                       isotopes of Oxygen is : O¹⁶ , O¹⁷, O¹⁸

4 0
3 years ago
A substance that forms a vapor is generally in what physical state at room temperature?liquid or solidsolidliquidgas
Evgesh-ka [11]

The answer is liquid or solid.

That is a substance that forms a vapor is generally in liquid or solid physical state.

The substance that is in liquid or solid physical state, forms vapor.

When heated solid and liquid can be converted into vapor so the answer is solid or liquid is the physical state that forms vapors.

6 0
3 years ago
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