Question

A ball of mass m kg is rolled up a slope at an angle a to the horizontal, where sin a = 2/5. The ball passes a point A with speed 7ms.-1
A point B is 5 m further up the slope than point A. Find the time between passing
B on the way up and returning to B on the way down.

Answer 1

16.42 seconds will elapse between passing B on the way up and coming back to B on the way down.

What is the definition of Angular Speed?

The rate of change of angular displacement is defined as angular speed, and it is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular velocity

Given data;

sin a = 2/5

a=sin(2/5)

a=23°

The linear velocity is the product of the angular velocity and the length.

$\rm v= \omega r \\\\ \omega= 7/5 \\\\ \omega= 1.4 \ rad/sec$

The times between the two points are found as;

$\omega = \frac{\triangle \theta }{\triangle t} \\\\ t= \frac{23}{1.4} \\\\ t = 16.42 \ sec$

Hence, the time between passing B on the way up and returning to B on the way down will be 16.42 sec.

To learn more about the angular speed refer to the link;

brainly.com/question/9684874

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